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scZoUnD [109]
3 years ago
9

Can someone please help? This is the last question on my final.

Mathematics
2 answers:
Tresset [83]3 years ago
5 0

Answer:C

Step-by-step explanation:

pashok25 [27]3 years ago
3 0
Correct Answer is 15 feet t= 0
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Nora must create a 4-character password to login to a website. The password must have three letters followed by a single digit,
patriot [66]

Answer:

The outcomes are {1nor} , {2nor}, {3nor}, {4nor}, {5nor}, {6nor}, {7nor}, {8nor}, {9nor}

Step-by-step explanation:

The outcomes are {1nor} , {2nor}, {3nor}, {4nor}, {5nor}, {6nor}, {7nor}, {8nor}, {9nor}

Reason-

0 can not be possible because if 0 is the first digit then , it will become the 3-digit password , not 4-digit

3 0
2 years ago
How can you write the expression with rationalized denominator? 2+sqrt3(3)/sqrt3(6)
joja [24]
So we have a 6 at the bottom, and the root is 3, so hmm how to take it out, simple enough, just let's get something to make the 6 a 6³, so it comes out of the root

so 

\bf \cfrac{2+\sqrt[3]{3}}{\sqrt[3]{6}}\cdot \cfrac{\sqrt[3]{6^2}}{\sqrt[3]{6^2}}\implies \cfrac{(2+\sqrt[3]{3})(\sqrt[3]{6^2})}{(\sqrt[3]{6})(\sqrt[3]{6^2})}\implies \cfrac{2\sqrt[3]{36}+\sqrt[3]{3}\cdot \sqrt[3]{36}}{\sqrt[3]{6^3}}
\\\\\\
\cfrac{2\sqrt[3]{36}+\sqrt[3]{3\cdot 36}}{6}\implies \cfrac{2\sqrt[3]{36}+\sqrt[3]{108}}{6}\implies \cfrac{2\sqrt[3]{36}+\sqrt[3]{3^3\cdot 4}}{6}
\\\\\\
\cfrac{2\sqrt[3]{36}+3\sqrt[3]{ 4}}{6}
8 0
3 years ago
Please help me solve this I forgot how to
RideAnS [48]
2.5 

hope it helps//...,d/cmn/lsjdhc;ljwknefv


4 0
3 years ago
Can someone please help me with the question in the attachment? I will mark you as brainliest!​
san4es73 [151]

Answer:

a=327 m=416

Step-by-step explanation:

subtract the numbers and add to make sure ur answer is correct

8 0
2 years ago
Read 2 more answers
How do I solve this question?
Yuri [45]
It's 18/100. The reduced / simplest form is 9/50 because you divide it by 2 since it's the GCS.
4 0
2 years ago
Read 2 more answers
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