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2 years ago

A set of numbers is shown below:

Mathematics

1 answer:

SVEN [57.7K]2 years ago

7 0

Answer:

{2,4,6}

Step-by-step explanation:

Hope it helps you

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Use the elimination method to solve the system of equations. Choose the correct ordered pair.

ki77a [65]

You answer is A. You have to substitute the values of x and y into the equation.

(3*1)= 4-1

4-(2*1)=2

(4,1)
(x,y)

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3 years ago

Probability question. Please answer with work attached.

musickatia [10]

Answer:

B. (0.61)

Step-by-step explanation:

Well, first I created venn diagram to help separate my work, then I subtracted .22 from each "probability sections" then I added them up to get .61

Work explains a lot.

Hope it helped. :)

8 0

3 years ago

Ken said that he is going to reduce the number of calories that he eats during the day. Ken's trainer asked him to start off sma

abruzzese [7]

2.200 or 2,200????????????

4 0

3 years ago

Prove that the product of any two consecutive natural numbers is even.

Vitek1552 [10]

Answer with Step-by-step explanation:

Let us assume the 2 consecutive natural numbers are 'n' and 'n+1'

Thus the product of the 2 numbers is given by

$Product=n(n+1)\\\\$

We know that the sum of 'n' consecutive natural numbers starting from 1 is

$S_n=\frac{n(n+1)}{2}\\\\\therefore n(n+1)=2\times S_n............(i)$

Thus from equation 'i' we can write

$Product=2\times S_n$

As we know that any number multiplied by 2 is even thus we conclude that the product of 2 consecutive numbers is even.

6 0

3 years ago

The antibiotic clarithromycin is eliminated from the body according to the formula A(t) = 500e−0.1386t, where A is the amount re

PolarNik [594]

Answer:

Time(t) = 11.61 hours (Rounded to two decimal place)

Step-by-step explanation:

Given: The antibiotic clarithromycin is eliminated from the body according to the formula:

$A(t) = 500e^{-0.1386t}$ ......[1]

where;

A - Amount remaining in the body(in milligram)

t - time in hours after the drug reaches peak concentration.

Given: Amount of drug in the body is reduced to 100 milligrams.

then,

Substitute the value of A = 100 milligrams in [1] we get;

$100= 500e^{-0.1386t}$

Divide both sides by 500 we get;

$\frac{100}{500}=\frac{ 500e^{-0.1386t}}{500}$

Simplify:

$\frac{1}{5} = e^{-0.1386t}$

Taking logarithm both sides with base e, then we have;

$\log_e (\frac{1}{5})= \log_e (e^{-0.1386t})$

$\log_e (\frac{1}{5})=-0.1386t$ [ Using $\log_e e^a =a$ ]

$\log_e (0.2)=-0.1386t$

$-1.6094379124341 = -0.1386t$

[using value of $\log_e (0.2) = -1.6094379124341$ ]

then;

$t = \frac{-1.6094379124341}{-0.1386}$

Simplify:

t ≈11.61 hours.

Therefore, the time 11.61 hours(Rounded two decimal place) will pass before the amount of drug in the body is reduced to 100 milligrams

6 0

2 years ago