9a-18b+21c apply distributive property to factor out gcf of all three terms
2 answers:
Answer:
Step-by-step explanation:
We are asked to factor out GCF of expression using distributive property.
We can see that greatest common factor of each term of our given expression is 3.
Using distributive property , we will factor out 3 from our expression as:
Therefore, our required expression would be .
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Gg easy
remember
(x^m)/(x^n)=x^(m-n)
and
(x^m)^n=x^(mn)
and
(xyz)^m=(x^m)(y^m)(z^m)
and
(m/n)^a=(m^a)/(n^a)
and
x^-n=1/(x^n)
so
=
=
=
=
=
remember
(x^m)/(x^n)=x^(m-n)
and
(x^m)^n=x^(mn)
and
(xyz)^m=(x^m)(y^m)(z^m)
and
(m/n)^a=(m^a)/(n^a)
and
x^-n=1/(x^n)
so