Question

9a-18b+21c apply distributive property to factor out gcf of all three terms

Answer 1

Answer:

$3(3a-6b+7c)$

Step-by-step explanation:

We are asked to factor out GCF of expression $9a-18b+21c$ using distributive property.

We can see that greatest common factor of each term of our given expression is 3.

$3\cdot 3a-3\cdot 6b+3\cdot 7c$

Using distributive property $a(b+c)=ab+ac$, we will factor out 3 from our expression as:

$3(3a-6b+7c)$

Therefore, our required expression would be $3(3a-6b+7c)$.

Answer 2

The greatest common factor of 9, 18 and 21 is 3 so that is the number that we'll factor out

to do this divide all three numbers by 3 to get

3(3a-6b+7c)

I hope I've helped!