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gavmur [86]
3 years ago
12

9a-18b+21c apply distributive property to factor out gcf of all three terms

Mathematics
2 answers:
Sonja [21]3 years ago
4 0

Answer:

3(3a-6b+7c)

Step-by-step explanation:

We are asked to factor out GCF of expression 9a-18b+21c using distributive property.

We can see that greatest common factor of each term of our given expression is 3.

3\cdot 3a-3\cdot 6b+3\cdot 7c

Using distributive property a(b+c)=ab+ac, we will factor out 3 from our expression as:

3(3a-6b+7c)

Therefore, our required expression would be 3(3a-6b+7c).

Evgesh-ka [11]3 years ago
3 0
The greatest common factor of 9, 18 and 21 is 3 so that is the number that we'll factor out

to do this divide all three numbers by 3 to get

3(3a-6b+7c)

I hope I've helped!
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