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3 years ago

Olivia bought snacks for her team's practice. She bought a bag of popcorn for $3.39

Mathematics

1 answer:

NeTakaya3 years ago

8 0

The answer is D because of the price range and the bag of popcorn not being multiplied by 4

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What is the answer to 3/4 / 1/8?

Nataly [62]

Answer:

Step-by-step explanation:

$\frac{3}{4} \div \frac{1}{8} \\ = \frac{3}{4} \times 8 \\ = 3 \times 2 \\ = 6$

4 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csec%5Cleft%28x%5Cright%29%7D%7B%5Ccos%5Cleft%28x%5Cright%29%7D-%5Cfrac%7B%5Csin%5

DanielleElmas [232]

Answer:

Step-by-step explanation:

First, convert all the secants and cosecants to cosine and sine, respectively. Recall that $csc(x)=1/sin(x)$ and $sec(x)=1/cos(x)$ .

Thus:

$\frac{sec(x)}{cos(x)} -\frac{sin(x)}{csc(x)cos^2(x)}$

$=\frac{\frac{1}{cos(x)} }{cos(x)} -\frac{sin(x)}{\frac{1}{sin(x)}cos^2(x) }$

Let's do the first part first: (Recall how to divide fractions)

$\frac{\frac{1}{cos(x)} }{cos(x)}=\frac{1}{cos(x)} \cdot \frac{1}{cos(x)}=\frac{1}{cos^2(x)}$

For the second term:

$\frac{sin(x)}{\frac{cos^2(x)}{sin(x)} } =\frac{sin(x)}{1} \cdot\frac{sin(x)}{cos^2(x)}=\frac{sin^2(x)}{cos^2(x)}$

So, all together: (same denominator; combine terms)

$\frac{1}{cos^2(x)}-\frac{sin^2(x)}{cos^2(x)}=\frac{1-sin^2(x)}{cos^2(x)}$

Note the numerator; it can be derived from the Pythagorean Identity:

$sin^2(x)+cos^2(x)=1; cos^2(x)=1-sin^2(x)$

Thus, we can substitute the numerator:

$\frac{1-sin^2(x)}{cos^2(x)}=\frac{cos^2(x)}{cos^2(x)}=1$

Everything simplifies to 1.

7 0

3 years ago

A DVD player with a list price of $100 is marked down

dsp73

Answer:

$56

Step-by-step explanation:

100 - (100(0.30)) = 100 - 30 = 70

70 - (70(0.20)) = 70 - 14 = 56

5 0

3 years ago

Factor Polynomial 3y^2+y-14

iris [78.8K]

Answer:

Factored Form: ( y - 2 )( 3y + 7 )

Step-by-step explanation:

1. Let us first write down the problem at hand: 3y^2 + y - 14

2. Now let us break this expression into groups:

3y^2 - 6y + 7y - 14 ⇒ ( 3y^2 - 6y )( 7y - 14 )

3. Factor 3y from 3y^2 - 6y:

3y^2 - 6y ⇒ 3y( y - 2 )

4. Factor 7 from 7y - 14:

7y - 14 ⇒ 7( y - 2 )

5. Substitute Step #3, 4 ⇒ Step #2:

3y( y - 2 ) + 7( y - 2 )

6. Factor common term y - 2:

Answer: ( y - 2 )( 3y + 7 )

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3 years ago

Prove that: u+v+w=0 = uxv = vxw = wxu

Misha Larkins [42]

Posting screenshot of my answer in the linked question in case it gets deleted.

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3 years ago