What times 7 equals 56

find the mean, median, and mode of the data set. round to the nearest tenth. 7,7,14,15,4,1,7,2,15,9,5

Arisa [49]

Here is the mean, median, and mode:

Mean: 1+2+4+5+7+7+7+9+14+15+15 = 86/11 ≈ 7.82
Median: 7
Mode: 7

To find the mean add up all the numbers and divide by the number of numbers

To find the median you just keep on crossing of numbers left to right until you get the middle number

To find the mode just look at which number is most commonly seen

Hope this helps!

5 0

3 years ago

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Please don't answer wrong.

Tamiku [17]

Answer:

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<u>Equation of a circle</u>

$(x-a)^2+(y-b)^2=r^2$

where:

(a, b) is the center
r is the radius

Given equation: $x^2+y^2=6.25$

Comparing the given equation with the general equation of a circle, the given equation is a <u>circle</u> with:

center = (0, 0)
radius = $\sqrt{6.25}=2.5$

To draw the circle, place the point of a compass on the origin. Make the width of the compass 2.5 units, then draw a circle about the origin.

Given equation: $x+y=1.5$

Rearrange the given equation to make y the subject: $y=-x+1.5$

Find two points on the line:

$x=-2 \implies -(-2)+1.5=3.5\implies (-2,3.5)$

$x=2 \implies -(2)+1.5\implies-0.5\implies (2,-0.5)$

Plot the found points and draw a straight line through them.

The <u>points of intersection</u> of the circle and the straight line are the solutions to the equation.

To solve this algebraically, substitute $y=-x+1.5$ into the equation of the circle to create a quadratic:

$\implies x^2+(-x+1.5)^2=6.25$

$\implies x^2+x^2-3x+2.25=6.25$

$\implies 2x^2-3x-4=0$

Now use the quadratic formula to solve for x:

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0$

$\implies x=\dfrac{-(-3) \pm \sqrt{(-3)^2-4(2)(-4)}}{2(2)}$

$\implies x=\dfrac{3 \pm \sqrt{41}}{4}$

To find the coordinates of the points of intersection, substitute the found values of x into $y=-x+1.5$

$\implies y=-\left(\dfrac{3 + \sqrt{41}}{4}\right)+1.5=\dfrac{3-\sqrt{41}}{4}$

$\implies y=-\left(\dfrac{3 - \sqrt{41}}{4}\right)+1.5=\dfrac{3+\sqrt{41}}{4}$

Therefore, the two points of intersection are:

$\left(\dfrac{3 + \sqrt{41}}{4},\dfrac{3-\sqrt{41}}{4}\right) \textsf{ and }\left(\dfrac{3 - \sqrt{41}}{4},\dfrac{3+\sqrt{41}}{4}\right)$

Or as decimals to 2 d.p.:

(2.35, -0.85) and (-0.85, 2.35)

6 0

2 years ago

A snack bar sells two sizes of snack packs. A large snack pack costs 5 dollars. A small snack pack costs 3 dollars. In one day t

il63 [147K]

X=cost of large snack Y=cost of small snack X+Y=60 5X+3Y=220 To solve for y, solve x+y=60 for x. Subtract y from both sides so you're left with x=-y+60. You now plug in -y+60 for x in the second equation. 5(-y+60)+3y=220 -5y+300+3y=220 -2y+300=220 -2y=-80 Y=40 40 small snack packs is the final answer

7 0

3 years ago

How to add the integers -7 and -5 plzzz help

padilas [110]

Answer:

oh its really easy

so for -7 you would just count up but negatives so -7 and -5= -13 :)

Step-by-step explanation:

7 0

3 years ago

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NEED ANSWER ASAP pls

EleoNora [17]

Answer:

Let F = Fran's income

Let W = Winston's income

Combined income is 80000 ==> F + W = 80000

One quarter of Winston's income is the same as one-sixth of Fran's income ==>

(1/4)*W = (1/6)*F

Multiply the 2nd equation by 12 to clear the fractions

3*W = 2*F

Solve this equation for F

F = (3/2)*W

Substitute this value for F into the 1st equation

(3/2)*W + W = 80000

(5/2)*W = 80000

W = (2/5)*80000 = 32000

So F = 80000 - 32000 = 48000

So Winston earns 32000 and Fran earns 48000

Check: One quarter of Winston's income is 32000/4 = 8000

One sixth of Fran'e income is 48000/6 = 8000

Step-by-step explanation: Hope this helps

4 0

2 years ago