The Candle Factory is producing a new candle. It has a radius of 3 inches and a height of 5 inches. How much wax is needed to ma
2 answers:
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Answer:
A. 60 degrees
Step-by-step explanation:
Solution to sin(x/2)=(/2)
By looking at this equation, I can identify that the answer must be within the first quadrant since the numerator and denominator are both positive.
Since it is in the first quadrant, the range of the value of the answer must be between 0 degrees less than or equal to x less than or equal to 90 degrees.
I can also identify that this is a 30, 60, 90 degree triangle because it has a and 2 as the numerator and denominator; in this case this tells us that we are dealing with a 30, 60, 90 degree triangle because that is the only triangle with those 2 respective sides.
Once identifying those two pieces of information, we can then determine the answer.
Since sin is equal Opposite/Hypotenuse, we can then substitute the sides of the triangle (, 2) to find the angle (unknown).
So the equation would look like this,
Sinx/2=/2 (
representing the opposite side of the angle; 2 representing the Hypotenuse of the triangle)
We can then conclude that 60 degrees is the unknown angle, due to the nature of a 30 60 90 degree triangle.
*Use the attachment for reference
Therefore, the answer, 60 degrees, is a solution to the equation "sin(x/2)=(/2)"
Let 'a' be the number of ounces of 2%-solution in the 25-ounce mixture
and 'b' be the number of ounces of 5%-solution in the 25-ounce mixture.
Since, fluid ounces of each concentration should be combined to make 25 fl oz.
So, a+b=25 (Equation 1)
And, a container of 2% acid solution and a container of 5% acid solution should be combined to make 25 fl oz of 3.2% acid solution.
So, a of 2% + b of 5% = 3.2% of 25
Multiplying the above equation by 100, we get
(Equation 2)
Substituting the value of a=25-b in equation 2, we get
Since, a=25-b
a= 25-10
a=15.
So, 15 fluid ounces of 2% solution combined with 10 ounces of the 5% solution to create a 25-ounce mixture at 3.2% concentration of acid.