Answer:
a.
.
b. 
Step-by-step explanation:
By the definition, the expected value of a random variable X with probability mass function p is given by
where the sum runs over all the posible values of X. Given a function g, the random variable Y=g(X) is defined. Note that the function g induces a probability mass function P' given by P'(Y=k) = P(X=g^{-1}(k)) when the function g is bijective.
a. Note that for 1/3ln(2)+1/6ln(5) by choosing the function g(x) = ln(x) the expression coincides with E(g(x)), because if Y = g(x) then E(Y) = P'(Y=1)*ln(1)+P'(Y=2)*ln(2)+P'(Y=5)*ln(5) = P(X=1)*ln(1)+P(X=2)*ln(2)+P(X=5)*ln(5).
b. On the same fashion, the function g(x) = xe^{xt} fullfills the expression of E[g(X)]
Answer:
3h
hope this helps
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Step-by-step explanation:
Answer:
(-2x - 1) • (x + 3)
Step-by-step explanation:
3.2 Factoring 2x2 + 7x + 3
The first term is, 2x2 its coefficient is 2 .
The middle term is, +7x its coefficient is 7 .
The last term, "the constant", is +3
Step-1 : Multiply the coefficient of the first term by the constant 2 • 3 = 6
Step-2 : Find two factors of 6 whose sum equals the coefficient of the middle term, which is 7 .
-6 + -1 = -7
-3 + -2 = -5
-2 + -3 = -5
-1 + -6 = -7
1 + 6 = 7 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, 1 and 6
2x2 + 1x + 6x + 3
Step-4 : Add up the first 2 terms, pulling out like factors :
x • (2x+1)
Add up the last 2 terms, pulling out common factors :
3 • (2x+1)
Step-5 : Add up the four terms of step 4 :
(x+3) • (2x+1)
Which is the desired factorization
You can solve for X when you can single it out to one side of the equal sign, but if you have more than one variable of X, x^2 or x^3 it might be harder to get X