7•2=14
3.14•14=
Answer: 43.96 yds
(I hope this help :) sorry if I’m incorrect)
First thing you have to do is divide up the 3 columns on the right so that all of the squares are the same size. (I did that in black, you can see it on the picture I attached). Then total all of the little squares. I did this in red, and got 50. Now just count up how many of the lighter colored squares you have, I highlighted them in yellow on my picture. I got 14 light squares. So you end up with fourteen light squares out of 50 total squares, which is 14/50. *apologizes for the bad handwriting on the image I did it on phone. If that didn’t help just comment and let me know what’s still unclear.
If <em>a</em> is fixed and <em>b</em>,<em>c</em> are unknowns then the equation <em>b</em>+<em>c</em>=10-<em>a</em> has 11-<em>a</em> solutions. They are pairs (b,c): (0,10-a), (1,9-a), (2,8-a), ... (10-a,0). As <em>a</em> runs from 0 to 10 we have total number of solutions (11-0)+(11-1)+...(11-1)=11+10+...+1=(1+11)*11/2=66.
I would love to help! What's the question?
Answer:
its d
Step-by-step explanation:
he did one task in 2.25 mins so multiply by 10