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3 years ago

6

Shana wants to use all 62 feet of the fencing she has to make a rectangular run for her dog. She decides to make the length of t

he run 20 feet. She right and solve the equation

1 answer:

scZoUnD [109]3 years ago

8 0

2L + 2W = 62
2(20) + 2W=62
40+ 2W=62
62-40=22
2W=22
22 divided by 2 is 11

W= 11

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PLEASE HELP!!! 3.05

Brilliant_brown [7]

The new polynomial identity is 2(x² + 2xy + y²)

Given,

The polynomial identities

Column A Column B

(x − y) (x2 + 2xy + y2)

(x + y) (x2 − 2xy + y2)

(y + x) (ax + b)

(y − x) (cy + d)

We have to square an identity from column A and add it with any one identity from column B.

So,

Lets take (x + y)

(x + y)² = x² + 2xy + y²

We can add this identity with x² + 2xy + y² in column B.

That is,

x² + 2xy + y² + x² + 2xy + y²

= 2x² + 4xy +2 y²

= 2(x² + 2xy + y²)

That is,

The new polynomial identity is 2(x² + 2xy + y²)

Learn more about polynomial identity here;

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2 years ago

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Solve the equation.<br> –10x +1+ 7x= 37<br> Ox= -15<br> Ox = -12<br> Ox = 12<br> Ox = 15

erastova [34]

Answer:

Ox = 12

Step-by-step explanation:

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3 years ago

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Pleas help me find the answer and show the work to this question

lions [1.4K]

Answer:

$Leg\ 1 = 8$

$Leg\ 2 = 15$

Step-by-step explanation:

Given: See Attachment

Required

Determine the length of the legs

To do this, we apply Pythagoras theorem.

$Hyp^2 = Adj^2 + Opp^2$

In this case:

$17^2 = x^2 + (2x- 1)^2$

Open Bracket

$17^2 = x^2 + 4x^2- 2x-2x + 1$

$17^2 = 5x^2 - 4x + 1$

$289= 5x^2 - 4x + 1$

Collect Like Terms

$5x^2 - 4x + 1 - 289 = 0$

$5x^2 - 4x - 288 = 0$

Solving using quadratic formula:

$x = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}$

So:

$x = 8$ or $x = -7.2$

Since, x can't be negative, then:

$x = 8$

One of the leg is:

$Leg\ 1 = x$

$Leg\ 1 = 8$

$Leg\ 2 = 2x - 1$

$Leg\ 2 = 2*8 - 1$

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6 0

3 years ago

Consider the line y=-1/2x+8

OverLord2011 [107]

Given parameters:

Equation of the line is y = - $\frac{1}{2} x$ + 8

Unknown:

Slope of line parallel to this line = ?

Slope of line perpendicular = ?

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A line parallel to this line will have the same slope with it.

A line perpendicular will have the negative inverse of this slope;

Slope of line = - $\frac{1}{2}$

Slope of line parallel to this line = $-\frac{1}{2}$

Slope of line perpendicular = negative inverse = -( -( $\frac{1}{\frac{1}{2} }$ )) = 2

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3 years ago

Right triangles abc and dbc with right angle c are given below. If cos(a)=15,ab=12 and cd=2, find the length of bd.

dmitriy555 [2]

see the attached figure to better understand the problem

we have that

$cos(A)=\frac{1}{5} \\ AB=12\ units\\ CD=2\ units$

Step 1

<u>Find the value of AC</u>

we know that

in the right triangle ABC

$cos (A)=(AC/AB)\\AC=AB*cos(A)$

substitute the values in the formula

$AC=12*(1/5)\\ AC=2.4\ units$

Step 2

<u>Find the value of BC</u>

we know that

in the right triangle ABC

Applying the Pythagorean Theorem

$AB^{2} =AC^{2}+BC^{2}\\ BC^{2}=AB^{2} -AC^{2}$

substitute the values

$BC^{2}=12^{2} -2.4^{2}\\BC^{2}= 138.24\\ BC=11.76\ units$

Step 3

<u>Find the value of BD</u>

we know that

in the right triangle BCD

Applying the Pythagorean Theorem

$BD^{2} =DC^{2}+BC^{2}$

substitute the values

$BD^{2} =2^{2}+11.76^{2}$

$BD=11.93\ units$

therefore

<u>the answer is</u>

the length of BD is 11.93 units

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3 years ago

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