One integer is x
another integer is y
x=8y
xy=288
(8y)(y)=288
8y^2=288
Divide both sides by 8
y^2= 36
The square root of 36 is 6
y=6
x=8y = 8(6) = 48
x=48
Hello!
To solve this, lets put it into a system of equations where w=width and L=length.
2w+2L=80
L-8=w
To solve, we see that w=L-8. We can substitute this in the first equation to find L and then w.
2(L-8)+2L=80
2L-16+2L=80
4L-16+80
4L-16=80
4L=96
L=24
Now that we know L=24, we can find w. 24-8=16. Now we know that L=24 and w=16.
Lets check our answer. In our original system of equations, we have 48+32=80, which is true, and 24-8=16. Also, the perimeter must equal 80. 16+16+24+24=80.
As our final answer, the width of the pool is 16 feet, and the length is 24 feet.
Hope this helps!
Answer:
12 1/6
It wants me to add more but there's nothing to add
