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AleksandrR [38]
3 years ago
15

Please find the surface area

Mathematics
1 answer:
nevsk [136]3 years ago
5 0
4*(10*12/2)+4*(12*9)+(12*12)= 816 ft^2

the surface area is 816 ft^2.
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-3x - 3y - z= -6
kifflom [539]

Answer:

Ammm, I think the answer you have is wrong, but what I really think is that the equations you put in are not the right ones because the answer for these is "ugly" (decimals etc...). Want to check your equations?

Step-by-step explanation:

Here is a step by step explanation to your equations (I assumed +3z for the second but you can change it). You can edit it for your equations if you want to.

https://simplisico.com/share/q/QiWKOyN5uYgkSG4iBXOmdG0i

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3 years ago
Identify the domain and range
MA_775_DIABLO [31]

Answer:

domain is x axis range is the y axis

Step-by-step explanation:

7 0
3 years ago
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Please answer right ill give brainliest for sure to the right answerrr
Stolb23 [73]
It’s the third one ............
6 0
3 years ago
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Limit definition for slope of the graph, equation of tangent line point for<br> f(x)=2x^2 at x=(-1)
Tems11 [23]

The slope of the tangent line to f at x=-1 is given by the derivative of f at that point:

f'(-1)=\displaystyle\lim_{x\to-1}\frac{f(x)-f(-1)}{x-(-1)}=\lim_{x\to-1}\frac{2x^2-2}{x+1}

Factorize the numerator:

2x^2-2=2(x^2-1)=2(x-1)(x+1)

We have x approaching -1; in particular, this means x\neq-1, so that

\dfrac{2x^2-2}{x+1}=\dfrac{2(x-1)(x+1)}{x+1}=2(x-1)

Then

f'(-1)=\displaystyle\lim_{x\to-1}\frac{2x^2-2}{x+1}=\lim_{x\to-1}2(x-1)=2(-1-1)=-4

and the tangent line's equation is

y-f(-1)=f'(-1)(x-(-1))\implies y-4x-2

6 0
3 years ago
-1/2x-1/4(10x-9)=-(-7/4x+2)-x
Tems11 [23]

Answer:

x= 17/15

Step-by-step explanation:

−1/2 x- 1/4 (10x−9)=−( -7/4 x+2)−x

8 0
3 years ago
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