Solve the following system of equations
1 answer:
You might be interested in
To solve this problem, we need to first find the dimensions of the side of the blue and purple squares.
We're given that the purple (smaller) square has a side length of x inches.
We are also given that the blue band has a width of 5 inches.
Since the blue band surrounds the purple square on both sides, the length of the blue square is x+2(5)=x+10 inches.
The net area of the band is therefore the difference of the area of the blue square and the purple square, namely take out the area of the purple square from the blue.
Therefore
Area of band
[recall 
or 20(x+5) if you wish.
We're given that the purple (smaller) square has a side length of x inches.
We are also given that the blue band has a width of 5 inches.
Since the blue band surrounds the purple square on both sides, the length of the blue square is x+2(5)=x+10 inches.
The net area of the band is therefore the difference of the area of the blue square and the purple square, namely take out the area of the purple square from the blue.
Therefore
Area of band
Answer:
10 number of checks.
Cost = $6
Step-by-step explanation:
Given that:
Fixed Charges of first bank = $5
Charges of first bank per check = $0.10
Fixed Charges of second bank = $4
Charges of second bank per check = $0.20
To find:
Number of checks such that the charges for the banks become the same?
Solution:
Let the number of checks =
Cost for the first bank for checks = $5 + $0.10
Cost for the second bank for checks = $4 + $0.20
As per question statement, both the costs are the same.
Comparing the values:
So, for 10 number of checks the cost will be same.
The cost = 4 + 0.20 10 = <em>$6</em>