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KiRa [710]
3 years ago
13

Explain how you can find 4 times 754 using two different methods

Mathematics
1 answer:
Rufina [12.5K]3 years ago
4 0
The simple way which is 4x754
Or add 754, 4 times.
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State the commutative property of addition using the variables a and b.
Verdich [7]

Answer:

a+b=b+a

Step-by-step explanation:

so 7+4=12 and 4+7=12 so addition is commutative

7 0
4 years ago
Read 2 more answers
Quadrilateral A'B'C'D'is the result of rotating quadrilateral ABCD by 60° about the origin.
Slav-nsk [51]

Answer:

a. No

b. Yes

c. No

Step-by-step explanation:

a. For BC and B'C to both be parallel to the y-axis when BC is parallel to the y-axis the figure must be rotated by a multiple of 180 degrees.

b. When you rotate a figure none of the angles in the figure change.

c. For D and D' to have the same coordinates the figure must be rotated by 360.

6 0
3 years ago
How far is a chord of length 8 cm from the centre of a circle of radius 5 cm
ivann1987 [24]
  • Answer:

<em>OB = 3 cm</em>

  • Step-by-step explanation:

<em>AO = radius = 5 cm</em>

<em>AB = 8cm/2 = 4 cm</em>

<em>Pythagora</em>

<em>OB² = AO² - AB²</em>

<em>= (5cm)² - (4cm)²</em>

<em>= 25cm² - 16cm²</em>

<em>= 9 cm²</em>

<em>OB = √9cm²</em>

<em>= 3 cm</em>

8 0
4 years ago
Find a fraction that, when multiplied by 1/3, is less than 2/7. Justify your answer.
Illusion [34]

Step-by-step explanation:

x <  \frac{6}{7}

All the fractions which less than (6/7) will be true

The steps of the solution in the above photo

I hope that is useful for you :)

8 0
3 years ago
Read 2 more answers
Kayla's making ribbons for school spirit day a roll of ribbon is 32 ft long for each individual ribbon she needs .64 ft how many
svp [43]

Kayla can make 50 ribbons for the show using 32 feet ribbon

<u>Solution:</u>

Given, Kayla's making ribbons for school spirit day a roll of ribbon is 32 ft long  And for each individual ribbon she needs 0.64 ft  

We have to find how many ribbons can she make for her old show.

Number of ribbons that can be made is found out by dividing total available ribbon by ribbon length required for single ribbon

\text { number of ribbons can be made }=\frac{\text { total available ribbon length. }}{\text { ribbon length required for single ribbon }}

\begin{array}{l}{=\frac{\text { total } 32 \text { feet }}{0.64 \text { for each ribbon }}} \\\\ {=\frac{32}{0.64}} \\\\ {=50 \text { ribbons }}\end{array}

Hence, Kayla can make 50 ribbons for the show using 32 feet ribbon.

8 0
4 years ago
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