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3 years ago

What is the answer to 8k-4(k-1)+7-k

Mathematics

2 answers:

seropon [69]3 years ago

8 0

8k-4k+4+7-k =
8k-4k-k+4+7 =
3k+11

kipiarov [429]3 years ago

3 0

Well first you have fallow the pemdas rules this means you have to solve your eeequation in order from parenthesis, exponents, multiplication, division, addition, and last subtraction... So first you have to do distributive property with you -4 and teh parenthesis this gives you 8k-4k+1+7-k now you have to add or subtract you common like terms( common like terms are terms that have the same thing for example 8k,-4k, and k are coomon like terms and 1 and 7 are coomon like terms) when you add them you will eb able to get your final answer.... Your answer should be "3k+8"\

Now if you wnat to solve for k you have to set every number aside to leave the k by itself. First subtract the 8 to the right side (you do this because 8 is a positive and the only way to get rid of a positive is with a negative) so now you should be left with 3k=-8 now our final step to leave k by itself is divide 3 in both sides( you do this because the only way to get rid of a multiplication is dividng) now you shoudl be left with K=-8/3. Good job!!!! we found our last result. this means that after everything we did your answer should be K=-8/3

Hope I explained well and that it helps you

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Please help! I will give 50 points and brainliest.

QveST [7]

Answer:

Step-by-step explanation:

f * g = (x^2 + 3x - 4) (x+4)

open bracket

x((x^2 + 3x - 4) + 4 (x^2 + 3x - 4)

x³ +3x²-4x+x²+12x-16

x³+3x²+x²-4x+12x-16

x³+4x²+8x-16 (domain is all real numbers.

f/g = (x^2 + 3x - 4)/(x+4)

factorising (x^2 + 3x - 4)

x²+4x-x_4

x(x+4) -1 (x+4)

(x+4)(x-1)

f/g = (x^2 + 3x - 4)/(x+4) =(x+4)(x-1)/(x+4) = (x-1)

Before factorisation, this was a rational function so the domain is all real numbers excluding any value that would make the denominator equal zero.

Hence I got x - 1, and x cannot equal -4

So the domain is just all real numbers without -4

8 0

2 years ago

2: A bag contains 5 black counters, 4 blue counters, and

drek231 [11]

Answer:

The probability that the counter was blue is $\mathbf{\frac{2}{5}}$

Step-by-step explanation:

Number of black Counters = 5

Number of blue Counters = 4

Number of white Counters = 1

We need to write down the probability that the counter was blue.

First find Total Counters

Total Counters = Number of black Counters + Number of blue Counters + Number of white Counters

Total Counters = 5+4+1

Total Counters = 10

Now, we need to find probability that the counter taken was blue

The formula used is:

$Probability= \frac{Number\:of\:favourable\:outcomes}{Total\:outcomes}$

There are 4 blue counters in the back, so Favourable outcomes = 4

$Probability= \frac{Number\:of\:favourable\:outcomes}{Total\:outcomes}\\Probability= \frac{4}{10}\\Probability= \frac{2}{5}$

The probability that the counter was blue is $\mathbf{\frac{2}{5}}$

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