Answer: Yes. When you solve your equations, you're solutions will change a little bit. It's good because it'll give you the right answer.
I hope this helps you and I hope it's right. ☺
Y = 16x^2 + 36
Lets find the intercepts, making x and y to zero and solving:
<span>0 = 16x^2 + 36
</span><span>16x^2 = -36
</span>therefore there is not x-intercept, that is, when y equals zero the function does not have a value, is not defined.
Now, the y intercept, that is when x equals zero:
<span>y = 16x^2 + 36
</span><span>y = 16(0)^2 + 36
</span>y = 36
so, when x = 0, y = 36, that is, the function hits the y axis when x = 0
The area of the parallelogram spanned by the given vectors is equal to the magnitude of their cross product.
(i + j + k) × (-2i + 3j + k)
= -2 (i × i) - 2 (j × i) - 2 (k × i)
… + 3 (i × j) + 3 (j × j) + 3 (k × j)
… + (i × k) + (j × k) + (k × k)
= - 2 (j × i) - 2 (k × i) + 3 (i × j) + 3 (k × j) + (i × k) + (j × k)
= 2 (i × j) - 2 (k × i) + 3 (i × j) - 3 (j × k) - (k × i) + (j × k)
= 5 (i × j) - 3 (k × i) - 2 (j × k)
= 5 k - 3 j - 2 i
Then the area of the parallelogram is
||-2 i - 3 j + 5 k|| = √((-2)² + (-3)² + 5²) = √38
Answer:
No
Step-by-step explanation:
