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UkoKoshka [18]
3 years ago
6

The system shown is____. 1.inconsistent 2.equivalent 3.consistent ​

Mathematics
2 answers:
amid [387]3 years ago
4 0
3. The correct answer is Consistent
leonid [27]3 years ago
3 0

Answer:

A. inconsistent

Step-by-step explanation:

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A man invests a total of $9,493in two savings accounts. One account yields 9% simple interest and the other 10% simple interest.
Agata [3.3K]

Answer:

$1850

Step-by-step explanation:

Given

  • The person invests a total of $9493
  • Amount invested in 9% Simple interest account =x
  • Amount invested in 10% Simple interest account= 9493-x
  • Earnings in Interest=$930.8

The simple interest formula

S.I=\frac{P\times T\times R}{100}

where

  • S.I is simple interest
  • P is principle invested
  • T is time period
  • R is rate of interest

There fore total interest

=930.8= \frac{x\times 1\times 9}{100} +\frac{(9493-x)\times 1\times 10}{100}\\930.8=\frac{9x+94930-10x}{100}\\93080=94930-x\\x=94930-93080\\x=1850

Therefore x=1850

⇒Amount invested in 9% account= $1850

4 0
3 years ago
EASY MATH!!! GIVING BRAINLIEST IF FAST!!
maksim [4K]

Answer:

a

Step-by-step explanation:

In any function of the form f(x) = a(b^x), the initial value is always <em>a</em> because it is not dependent on <em>x</em>.

8 0
4 years ago
Determine the measure of an angle whose measure is 17 times that of its complement
Andrei [34K]
Complementary angles add to 90 degrees,
85 is 17 times greater than 5, 85 + 5 = 90
5 0
3 years ago
Read 2 more answers
The table shows the heights of 40 students in a class.
Studentka2010 [4]

Answer:

Step-by-step explanation:

Hello!

a)

The given information is displayed in a frequency table, since the variable of interest "height of a student" is a continuous quantitative variable the possible values of height are arranged in class intervals.

To calculate the mean for data organized in this type of table you have to use the following formula:

X[bar]= (∑x'fi)/n

Where

x' represents the class mark of each class interval and is calculated as (Upper bond + Lower bond)/2

fi represents the observed frequency for each class

n is the total of observations, you can calculate it as ∑fi

<u>Class marks:</u>

x₁'= (120+124)/2= 122

x₂'= (124+128)/2= 126

x₃'= (128+132)/2= 130

x₄'= (132+136)/2= 134

x₅'= (136+140)/2= 138

Note: all class marks are always within the bonds of its class interval, and their difference is equal to the amplitude of the intervals.

n= 7 + 8 + 13 + 9 + 3= 40

X[bar]= (∑x'fi)/n= [(x₁'*f₁)+(x₂'*f₂)+(x₃'*f₃)+(x₄'*f₄)+(x₅'*f₅)]/n) = [(122*7)+(126*8)+(130*13)+(134*9)+(138*3)]/40= 129.3

The estimated average height is 129.3cm

b)

This average value is estimated because it wasn't calculated using the exact data measured from the 40 students.

The measurements are arranged in class intervals, so you know, for example, that 7 of the students measured sized between 120 and 124 cm (and so on with the rest of the intervals), but you do not know what values those measurements and thus estimated a  mean value within the interval to calculate the mean of the sample.

I hope this helps!

4 0
4 years ago
*WILL MARK BRAINLIEST*
user100 [1]

Answer:

64 + 64sqrt(3)

174.9 cm²

Step-by-step explanation:

AD/2 = 8cos(60) = 4

AD = 8 cm

Height of each triangle = 8sin(60)

= 4sqrt(3)

sqrt: square root

Area = 8² + 4(½ × 8 × 4sqrt(3))

= 64 + 64sqrt(3) cm²

= 174.8512517 cm²

5 0
3 years ago
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