Think of A as a constant - with D it's 117 and with M it's 88
So the difference between D and M is 29 (117-88)
We also know that M + D = 161
Let's substitute in the problem We will leave M equal to M and rewrite D as M+29 since it is 29 kg heavier.
M + M + 29 -161 or 2M +29 = 161 Subtracting 29 from both sides we get 2M=122
Now divide both sides two and get M=61
Since D is M+29 it is 61+29 or 100kg
Finally A + M = 88 A + 61 - 88 Subtract 61 from both sides and get A=17
So there you have it:
A=17kg
M=61kg
D=100kg and it works in all three equation in your problem (try it to check)
Answer:
9 : 10
Step-by-step explanation:
First the ratio will be 63 : 70
Now, we have to simplify! The GCF (greatest common factor) is 7, so let's divide both numbers by 7 to maintain equality.
63/7 = 9
70/7 = 10
9 : 10 is the final answer!
A
Step-by-step explanation:
I think if i am wrong i am dum
9514 1404 393
Answer:
- -√5
- 3/5
- -4/5
Step-by-step explanation:
The relevant relations are ...
sec = ±√(tan² +1)
cos = 1/sec
csc = 1/sin = ±1/√(1 -cos²)
Sine and Cosecant are positive in quadrants I and II. Cosine and Secant are positive in quadrants I and IV.
__
1. sec(θ) = -√((-2)² +1) = -√5
2. cos(θ) = 1/sec(θ) = 1/(5/3) = 3/5
3. csc(θ) = -1/√(1 -(-3/5)²) = -√(16/25) = -4/5
