3 years ago

GEOMETRY HELP PLEASE!!

1 answer:

8 0

I don't know exactly what "triangle proofs" represents, because there are varieties of proofs related to triangle.

But, as long as the geometric figures can be split into triangles, the proofs can be applied.

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If a 12-student class averaged 90 on a test, and a 20-student class averaged 80 on the test, then all 32 students averaged

Alexxx [7]

Let the marks of the students in class 1 be

$m_1, m_2, ....., m_1_2$

the average of these 12 marks is 90, so

$\frac{m_1+ m_2+ .....+ m_1_2}{12}=90$

which means

$m_1+ m_2+ .....+ m_1_2=90*12=1080$

similarly, let $n_1, n_2, ....., n_2_0$ be the marks of the students in the second class,

so $\frac{n_1+ n_2+ ..... n_2_0}{20}=80$

which means $n_1+ n_2+ ..... n_2_0=80*20=1600$

The 32 students averaged:

$\frac{(m_1+ m_2+ .....+ m_1_2)+(n_1+ n_2+ ..... n_2_0)}{12+20}= \frac{1080+1600}{32}= \frac{2680}{32}= 83.75$

5 0

3 years ago

Read 2 more answers

Find the GCF of the following set of numbers <br> 260, 80, 50

Vinvika [58]

Answer:

Step-by-step explanation:

The factors of 50 are: 1, 2, 5, 10, 25, 50

The factors of 80 are: 1, 2, 4, 5, 8, 10, 16, 20, 40, 80

The factors of 260 are: 1, 2, 4, 5, 10, 13, 20, 26, 52, 65, 130, 260

In all of these numbers, we can see that 10 is common throughout and 10 is also the greatest factor all these numbers share.

Hope this helps you :)