Answer:
Step-by-step explanation:
![P(t)=50001+Be^{-kt}](https://tex.z-dn.net/?f=P%28t%29%3D50001%2BBe%5E%7B-kt%7D)
If <em>t</em> is years since January 1, 2010, then on January 1, 2010, <em>t</em> = 0.
On April 1, 2010, there are 3 months from January 1, 2010. <em>t</em> = 0.25 (3 months ÷ 12 months)
At <em>t</em> = 0, <em>P</em>(<em>t</em>) = 500
![P(0)=500 = 50001+Be^{-k\times0} = 50001+B](https://tex.z-dn.net/?f=P%280%29%3D500%20%3D%2050001%2BBe%5E%7B-k%5Ctimes0%7D%20%3D%2050001%2BB)
![B = 500 - 50001 = -49501](https://tex.z-dn.net/?f=B%20%3D%20500%20-%2050001%20%3D%20-49501)
At <em>t</em> = 0.25, <em>P</em>(<em>t</em>) = 750
![P(0)=750 = 50001-49501e^{-k\times0.25}](https://tex.z-dn.net/?f=P%280%29%3D750%20%3D%2050001-49501e%5E%7B-k%5Ctimes0.25%7D)
![49501e^{-0.25k} = 50001](https://tex.z-dn.net/?f=49501e%5E%7B-0.25k%7D%20%3D%2050001)
![e^{-0.25k} =\dfrac{50001}{49501} = 1.0101](https://tex.z-dn.net/?f=e%5E%7B-0.25k%7D%20%3D%5Cdfrac%7B50001%7D%7B49501%7D%20%3D%201.0101)
![-0.25k = \ln1.0101 = 0.01](https://tex.z-dn.net/?f=-0.25k%20%3D%20%5Cln1.0101%20%3D%200.01)
![k = -\dfrac{0.01}{0.25} = -0.04](https://tex.z-dn.net/?f=k%20%3D%20-%5Cdfrac%7B0.01%7D%7B0.25%7D%20%3D%20-0.04)
Substituting for <em>B</em> and <em>k</em> in <em>P</em>(<em>t</em>),
![P(t)=50001-49501e^{-0,04t}](https://tex.z-dn.net/?f=P%28t%29%3D50001-49501e%5E%7B-0%2C04t%7D)
Answer:
So first you would do 15 x 7/8 which would get you 13.12500 but round it and you would get 13.125 as the original number. If you were trying to get the number it first asked you would do 15 x 13.125 = 196.87500, round that and you would get 196.875.
Answer:
12-3+4x6= 33, 33 divided by 3 is 11
Step-by-step explanation:
11
Answer: That is a personal opinion question. I'd agree with Rhett on this, mainly because I love pizza, and you can buy 1 pizza for the price of 2 with a larger diameter, meaning more pizza per slice than bying the smaller ones.
Step-by-step explanation: