The length of AB is (x + 4) cm and the values of a and be are a = 10, b = 4
A rectangle is a quadrilateral in which opposite sides are equal and parallel to each other. The area of a rectangle is:
Area = length * width
From the image:
Length of AB = x + 4
Length of BC = x + 6
The area of rectangle ABCD = Length of AB * Length of BC
28 = (x + 4)(x + 6)
x² + 10x + 24 = 28
x² + 10x = 4
Comparing with x² + ax = b gives:
a = 10, b = 4
Therefore the length of AB is (x + 4) cm and the values of a and be are a = 10, b = 4
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The value of x must be 25.0. The correct option is the second option- 25.0
<h3>Solving Linear equations </h3>
From the question, we are to determine the value of x
From the given diagram, we can write that
m ∠SOR + m ∠UOR + m ∠TOU = 180° (<em>Sum of angles on a straight line</em>)
∴ (2x +8)° + (3x - 14)° + (3x -14)° = 180°
2x° + 8° + 3x° -14° + 3x° -14° = 180°
Collect like terms
2x° + 3x° + 3x° + 8° - 14° -14° = 180°
8x° -20° = 180°
8x° = 180° + 20°
8x° = 200°
x = 200/8
x = 25.0
Hence, the value of x must be 25.0. The correct option is the second option- 25.0
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If you're trying to factor it, the answer would be >> 2<span>(<span>x+y</span><span>)
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Answer:
the 7th
0.007805 or 59 / 756
Step-by-step explanation:
To determine the Friday that he needed more pounds, determine the number of pounds he needed per dog for each Friday.
to do this, divide the total pounds by the number of dogs
on the 14th
3/8 ÷ 35 =
3/8 x 1/35 = 3/280
on the 7th
1/2 ÷ 27 =
1/2 x 1/27 = 1/54
to determine which fraction is larger multiply each by 100 to determine its percent
3/280 x 100 = 1.071
1/54 x 100 = 1.852
1/54 is larger. Thus, more pounds was needed on Friday the 7th
the difference between these fractions should be determined
- 
=
= 59 / 756
The difference is 50 because you are multiplying 50, 98 times
So when you multiply 50, 97 times you are one 50 less than 98
Proof: 98x50=4900
97x50=4850
4900-4850=50