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krok68 [10]
3 years ago
6

Four times the sum of three consecutive integers is 180 what are the integers

Mathematics
1 answer:
Novay_Z [31]3 years ago
7 0
45 x 4 = 180 so the answer is 45
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You can buy 6 cans for green beans at the Sendiks for $3.80. You can buy 12 of the same cans of beans at
sasho [114]

Answer:

Sendiks.

Step-by-step explanation:

Sendiks- 6 ÷ 3.80= $1.58 per can

Sam's Club- 12÷6.90= $1.74 per can

4 0
3 years ago
Please help solve last one
mr_godi [17]

Answer:

The answer would be 7(2x+3y+z) or 7(2x+3y+1z) (both would be considered as correct)

Step-by-step explanation:


5 0
3 years ago
Pleaseeeee helppppDetermine how many actual fish food boxes fit in the shipping box. Show your work. Find the volume of the ship
Alex Ar [27]

Shipping box is a cube, with units

Fish food is an unitary cube, that means have x,y,z measures the same

Shipping box is a parallelepip box. Rectangular

Volume of shipping box is found by formula

V = X•Y•Z

X = 3ft, Y=3 3/4 ft, Z=3 1/4 ft

then V = (3•3+ 3•3/4)•(3+1/4) = (11 +1/4)• (3+1/4) = 33 + 11/4 + 3/4 + 1/16

V = 33 + 2 + 3/4+ 3/4 +1/16 = 35 + 25/16 = 34+ 9/16

Now, find volume using packing cubes

How many fish food boxes fit

In X direction it fits 3/(1/4) = 12

In Y direction it fits (3+3/4)/(1/4)= 15

In Z direction it fits (3+1/4)/(1/4) = 10

Now then multiply 12x15x10= 1800 fish boxes fit in larger box

3 0
1 year ago
What is the prime factorization of the number 55?
Simora [160]

Answer:

11 if im right :)

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the proporti
hodyreva [135]

Answer:

The sample size n = 4225

Step-by-step explanation:

We will use maximum error formula = \frac{z_{a} S.D}{\sqrt{n} }

but we will find sample size "n"

\sqrt{n}  = \frac{z_{a} S.D}{maximum error}

Squaring on both sides , we get

n  = (\frac{z_{a} S.D}{maximum error})^2

Given 99% confidence interval (z value) = 2.56

given maximum error = 0.02

n  = (\frac{z_{a} p(1-p)}{maximum error})^2

n≤ (\frac{2.56X\frac{1}{2} }{0.02}) ^{2}    ( here S.D = p(1-p) ≤ 1/2

on simplification , we get n = 4225

<u>Conclusion</u>:

The sample size of two samples is  n = 4225

<u>verification</u>:-

We will use maximum error formula = \frac{z_{a} S.D}{\sqrt{n} } = \frac{2.56 1/2}{\ \sqrt{4225} }  = 0.0196

substitute all values and simplify we get maximum error is 0.02

4 0
3 years ago
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