Here is my work:
Distance is 1.2 miles
:-)
Distance is 1.2 miles
:-)
Luis has a pyramid shaped plant pot. It has a square base with a side length of 36 cm, and the height of the pot is 36 cm. Luis
1 answer:
Answer:
The required volume, if he wants to fill 75% of the pot's volume, is 11664cm³
Step-by-step explanation:
The volume of a pyramid is given as
Where V is the pot's volume, A is the base area and h is the height.
Our base is a square, so the base area, if s denotes the side length, would be s x s.
s = 36cm, therefore we have A = 36cm X 36cm = 1296cm².
The height is given as 36cm, therefore we have our volume to be:
Since Luis wants to fill 75% of the pot's volume with soil. Then it will take
Thus, the required volume, if he wants to fill 75% of the pot's volume, is 11664cm³
You might be interested in
It looks like the integral is
where <em>C</em> is the circle of radius 2 centered at the origin.
You can compute the line integral directly by parameterizing <em>C</em>. Let <em>x</em> = 2 cos(<em>t</em> ) and <em>y</em> = 2 sin(<em>t</em> ), with 0 ≤ <em>t</em> ≤ 2<em>π</em>. Then
Another way to do this is by applying Green's theorem. The integrand doesn't have any singularities on <em>C</em> nor in the region bounded by <em>C</em>, so
where <em>D</em> is the interior of <em>C</em>, i.e. the disk with radius 2 centered at the origin. But this integral is simply -2 times the area of the disk, so we get the same result: .