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Dennis_Churaev [7]
4 years ago
6

Amber spent 1,793.34 on a TV after an 18% discount and on an 8% tax. What was the original price of the TV?

Mathematics
1 answer:
Daniel [21]4 years ago
3 0
The original price of the TV was $1327.07
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Five whole numbers are written in order
jeka57 [31]

Answer:

x=7

y=8

Step-by-step explanation:

-Given that the mean and median is the same.

-Let b=mean =median

#Given that the set is arranged in order and is even:

median=\frac{n+1}{2}\\\\Median=3^{rd} \ term\\\\=x

Hence:

b=median=mean\\\\b=x\\\\\therefore mean=median=x

-Applying the mean formula:

\bar x=\frac{1}{n}\sum{x_i}\\\\\therefore 5x=4+6+x+y+10\\\\4x=20+y\\\\x=5+0.25y

#Since the number are in order:

6

Hence, x=7 and y=8

8 0
3 years ago
Find the distance between a and b.<br><br> ​<br><br> a = 9.21, b = –5.51<br><br> ​
cricket20 [7]
9.21 - (-5.51)
9.21 + 5.51 = 14.72
The distance is 14.72
5 0
3 years ago
Read 2 more answers
Simpify the expression. -2(y + 3) -7y
jenyasd209 [6]
-2y-6-7y
-9y-6
I hope that this helps!
4 0
3 years ago
What is 4x8 please answer I’ll give you 95 points
Rina8888 [55]

Answer:

32

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Consider the following division of polynomials.
Bond [772]

x^4=x^2\cdot x^2. Multiplying the denominator by x^2 gives

x^2(x^2+2x+8)=x^4+2x^3+8x^2

Subtracting this from the numerator gives a remainder of

(x^4+x^3+7x^2-6x+8)-(x^4+2x^3+8x^2)=-x^3-x^2-6x+8

-x^3=-x\cdot x^2. Multiplying the denominator by -x gives

-x(x^2+2x+8)=-x^3-2x^2-8x

and subtracting this from the previous remainder gives a new remainder of

(-x^3-x^2-6x+8)-(-x^3-2x^2-8x)=x^2+2x+8

This last remainder is exactly the same as the denominator, so x^2+2x+8 divides through it exactly and leaves us with 1.

What we showed here is that

\dfrac{x^4+x^3+7x^2-6x+8}{x^2+2x+8}=x^2-\dfrac{x^3+x^2+6x-8}{x^2+2x+8}

=x^2-x+\dfrac{x^2+2x+8}{x^2+2x+8}

=x^2-x+1

and this last expression is the quotient.

To verify this solution, we can simply multiply this by the original denominator:

(x^2+2x+8)(x^2-x+1)=x^2(x^2-x+1)+2x(x^2-x+1)+8(x^2-x+1)

=(x^4-x^3+x^2)+(2x^3-2x^2+2x)+(8x^2-8x+8)

=x^4+x^3+7x^2-6x+8

which matches the original numerator.

3 0
3 years ago
Read 2 more answers
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