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Katyanochek1 [597]
3 years ago
7

How does making a list help you find common factors

Mathematics
2 answers:
ElenaW [278]3 years ago
8 0
Making a list can help you find the GCF or the LCF.
Flura [38]3 years ago
6 0
Is the greatest factor that two or more numbers have in common. One way to find the GCF is to make lists of the factors for two numbers and then choose the greatest factor that the two factors have in common.
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2PLSS NEED HELP.........
Nonamiya [84]

Answer:

  right

Step-by-step explanation:

The side ratios are ...

  24 : 45 : 51 = 8 : 15 : 17

These numbers are a Pythagorean triple. The triangle is a right triangle.

__

24² + 45² = 576 +2025 = 2601 = 51² . . . . the Pythagorean theorem is satisfied

5 0
2 years ago
I need help for this question because I need to understand this topic!
irga5000 [103]

Answer:

  yes, brother can go

Step-by-step explanation:

Apparently, you're not to think to deeply about this function. Rather, you are to take the question at face value. It is asking if the value of T(3) is more than 58.

Evaluation of polynomials is facilitated by writing them in "Horner form."

  T(x) = ((x -2)x +1)x^2 +27

  T(3) = ((3 -2)3 +1)9 +27 = (3 +1)9 +27 = 36 +27

  T(3) = 63

The coldest temperature is supposed to be 63 degrees, which is above 58 degrees. Baby brother can come along.

8 0
3 years ago
Extra Example 3: Hazel has $23.28 in her purse. She has $5.60 more than Nixon.
sveticcg [70]

Answer:

Yolanda is correct.

Step-by-step explanation:

If Hazel has $23.28 and $5.60 more than Nixon, then Nixon will have $17.68 because 23.28-5.60 is 17.68.

The only way Paul would be right is if Nixon has $5.60 more than Hazel because 23.28+5.60 is 28.88.

4 0
3 years ago
The area of a rhombus is 40 in. If
polet [3.4K]

Answer:

10 in.

Step-by-step explanation:

The area of a rhombus is the product of the lengths of the diagonals divided by 2.

Let the diagonals be x and y.

area = xy/2

Here you have

area = 40 in.^2

x = 8 in.

We are looking for y, the other diagonal.

xy/2 = area

(8 in.)y/2 = 40 in.^2

(8 in.)y = 80 in.^2

y = 10 in.

Answer: The other diagonal has length 10 in.

7 0
3 years ago
Read 2 more answers
A runner, training for a competition, ran on a track every day for 10 weeks. The first week he ran 8 kilometers each day of the
Levart [38]

Answer:

Total = 686000 meters for 10 weeks 7 days a week.

Step-by-step explanation:

Let's solve this by doing the increase on just 1 training day per week. Then we can find the grand total for 7 days a week by multiplying by 7

a = 8000

n = 10

d = 400

Sum = (a + L)*n/2

  • L = a + (n - 1)*d
  • L = 8000 + (10 - 1)*400
  • L = 8000 + 9*400
  • L = 8000 + 3600
  • L = 11600 meters

Sum = (8000 + 11600)*10/2

Sum = 19600 * 10/2

Sum = 98000 meters.

This total represents 1 training day a week.

The total amount is 7 times this figure.

Total = 7 * 98000 = 686 000 meters.

3 0
3 years ago
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