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jenyasd209 [6]
3 years ago
6

PLEASE HELP!!!

Mathematics
1 answer:
anzhelika [568]3 years ago
6 0

For this specific problem, the standard error of the mean for a sample of 70 students would be 1.3745. I am hoping that this answer has satisfied your query about and it will be able to help you, thank you and have a nice day.

You might be interested in
Which statement is true about the equation? 3y-6x=-3
Mekhanik [1.2K]
<span>B.When x=-4, y=-9 and when x=2, y=3.

</span><span>3y-6x=-3
3(-9) - 6(-4)= -3
-27 +24 =-3
-3 = -3

</span>
<span>3y-6x=-3
3(3) -6 (2) = -3
9 - 12 = -3
-3 = -3
</span>
8 0
3 years ago
Pick a user for me (im so indecicive) most helpful answer gets brainlist ofc also lots of points, yw!
LUCKY_DIMON [66]

Answer:

I just answered the other question you asked. Why did you ask the same question twice? Also, I said the 1st one

Step-by-step explanation:

7 0
2 years ago
HELP ME TVT I beg you (answer by yes or no)
aliya0001 [1]

Answer:

1:yes 2:no 3:no 4:yes

Step-by-step explanation:

3*2=6 for the numerators

4*5=20 for the denominators

you can simplify this to make it 3/10 ✔️

2*5-10 for the numerators

6*5=30 for the denominators

you can simplify this to make it 1/3 ❌

1*1=1 for the numerators

10*5 for the denominators

you can turn this into 1/50 ❌

1*3=3 for the numerators

2*5=10 for the denominators

you can turn this into 3/10 ✔️

hope this helps! have a nice day! :)

5 0
2 years ago
What is the answer to 2x2
True [87]

Answer:

2 x 2 = 4

Step-by-step explanation:

Two cookies plus another two cookies is 4. You can also use a multiplication table. :)

6 0
3 years ago
Read 2 more answers
What is the center of the hyperbola whose equation is (y+3)^2/81-(x-6)^2/89=1?
xxMikexx [17]

We have been given an equation of hyperbola \frac{(y+3)^2}{81}-\frac{(x-6)^2}{89}=1. We are asked to find the center of hyperbola.  

We know that standard equation of a vertical hyperbola is in form \frac{(y-k)^2}{b^2}-\frac{(x-h)^2}{a^2}=1, where point (h,k) represents center of hyperbola.

Upon comparing our given equation with standard vertical hyperbola, we can see that the value of h is 6.

To find the value of k, we need to rewrite our equation as:

\frac{(y-(-3))^2}{81}-\frac{(x-6)^2}{89}=1

Now we can see that value of k is -3. Therefore, the vertex of given hyperbola will be at point (6,-3) and option D is the correct choice.

6 0
3 years ago
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