Solve for P and R. Don’t mind the top part.

A line segment AB has the coordinates A (2,3) AND B ( 8,11) answer the following questions (1) What is the slope of AB? (2) What

gizmo_the_mogwai [7]

Answer:

1) The slope of the line segment AB is $\frac{4}{3}$ .

2) The length of the line segment AB is 10.

3) The coordinates of the midpoint of the line segment AB is $M(x,y) = (5,7)$ .

4) The slope of a line perpendicular to line segment AB is $-\frac{3}{4}$ .

Step-by-step explanation:

1) Let $A(x,y) = (2,3)$ and $B(x,y) = (8,11)$ . From Analytical Geometry, we get that slope of AB ( $m_{AB}$ ), dimensionless, is determined by the following formula:

$m_{AB} = \frac{y_{B}-y_{A}}{x_{B}-x_{A}}$ (1)

If we know that $x_{A} = 2$ , $x_{B} = 8$ , $y_{A} = 3$ and $y_{B} = 11$ , the slope of the line segment is:

$m_{AB} = \frac{11-3}{8-2}$

$m_{AB} = \frac{4}{3}$

The slope of the line segment AB is $\frac{4}{3}$ .

2) The length of the line segment AB ( $l_{AB}$ ), dimensionless, can be calculated by the Pythagorean Theorem:

$l_{AB} =\sqrt{(x_{B}-x_{A})^{2}+(y_{B}-y_{A})^{2}}$ (2)

If we know that $x_{A} = 2$ , $x_{B} = 8$ , $y_{A} = 3$ and $y_{B} = 11$ , the length of the line segment AB is:

$l_{AB} = \sqrt{(8-2)^{2}+(11-3)^{2}}$

$l_{AB} = 10$

The length of the line segment AB is 10.

3) The coordinates of the midpoint of the line segment AB are, respectively:

$x_{M} = \frac{x_{A}+x_{B}}{2}$ (3)

$y_{M} = \frac{y_{A}+y_{B}}{2}$ (4)

If we know that $x_{A} = 2$ , $x_{B} = 8$ , $y_{A} = 3$ and $y_{B} = 11$ , the coordinates of the midpoint of the line segment AB are, respectively:

$x_{M} = \frac{2+8}{2}$

$x_{M} = 5$

$y_{M} = \frac{3+11}{2}$

$y_{M} = 7$

The coordinates of the midpoint of the line segment AB is $M(x,y) = (5,7)$ .

4) From Analytical Geometry we can determine the slope of a line perpendicular to line segment AB as a function of the slope of the line segment:

$m_{\perp} = -\frac{1}{m_{AB}}$ (5)

If we know that $m_{AB} = \frac{4}{3}$ , then the slope of a line perpendicular to AB is:

$m_{\perp} = - \frac{1}{\frac{4}{3} }$

$m_{\perp} = -\frac{3}{4}$

The slope of a line perpendicular to line segment AB is $-\frac{3}{4}$ .

7 0

3 years ago

I don't understand this at all. can someone explain?

ElenaW [278]

Answer:

In order, your numbers are

22, 45, 75, 89, 89, 95, 100

The median is the number that is in the middle numbers of all your numbers. The median is 89, since it is in the very middle.

The mean is all your numbers added together and then divided by how ever many numbers you have. 22 + 45 + 75 + 89 + 89 + 95 + 100 = 515. Since you have 7 numbers, you would divide 515 by 7, which equals 73.5. The mean is 73.5.

The mode is the number that has the most numbers(not sure how to word it) Since 89 has two of the numbers, and no other numbers have duplicates, your mode is 89.

6 0

3 years ago

Question 2 (1 point) Saved

ziro4ka [17]

Answer: 5 pounds of ground beef for $11.50

Step-by-step explanation:

8 divided by $18.00

= $2.25

Then when you do that you go though and multiply each one

and when you get to answer C it does match.

hope this helps o_0

8 0