Find three consecutive odd integers whose sum is 21

jolli1 [7]

Hello.

The answer is choice A. angle 1 = 118, angle 2 = 118

Explanation:

The four angles above are congruent (meaning the same) to the ones beneath.

Angles 1 and 2 are also congruent, so they will measure the same.

Lets label the angles above A, B, C, D. B being the known angle, which is 118°. The angles beneath can be labelled E, F, G, H.

∠B ≅ ∠D

∠ABCD ≅ ∠EFGH

∠BD ≅ ∠FH

FH (or 1 and 2) equal 118.

4 0

4 years ago

La matemática financiera experimentó grandes avances con la creación de la banca y los negocios creados por los emprendedores. E

Tresset [83]

Answer:

c = $\frac{1}{10}$

f= 1500

Step-by-step explanation:

Tenemos la siguiente ecuación

$C = f+cm$

Tenemos los siguientes valores para m=15000, c = 3000 y para m = 20000, c=3500. Es decir, tenemos las siguientes ecuaciones

$3000=f+c15000, 3500=f+c20000$

Si restamos la segunda ecuación de la primera, tenemos que

$3500-3000 = f-f+(20000c-15000c)$

Luego

$500 = 5000c$

Entonces $c = \frac{500}{5000} = \frac{1}{10}$

Si tomamos la primera ecuación, tenemos que $3000-\frac{15000}{10} = f$ . Es decir,

$3000-1500 = f = 1500$

Esta solución, al plantear 2 ecuaciones y dos incógnitas, plantea un sistema dos por dos.

8 0

3 years ago

5x + y = 11 3x - y =9 What is the value of x and y

tatiyna

Answer:

x=2.5 ; y=-1.5

Step-by-step explanation:

Explaination in picture

6 0

3 years ago

Read 2 more answers

The base of an open rectangular box is of length (2x+5) cm and width x cm. The area of this base is 58cm^2. The height of the op

andreev551 [17]

B) $x =4.28$

C) volume = $135.25cm^3$ .

Step-by-step explanation:

Here we have , The base of an open rectangular box is of length (2x+5) cm and width x cm. The area of this base is 58cm^2. The height of the open box is (x-2) cm. We need to find the following :

a) show that 2x^2+5x-58=0

We know that area of rectangle = $length(width)$

⇒ $Area = length(width)$

Putting values according to question we get :

⇒ $58 = (2x+5)(x)$

⇒ $58 = (2x^2+5x)$

⇒ $2x^2+5x - 58 = 0$

b) solve the equation in the question above, giving your answer to 2 decimal places

Solving this equation :

⇒ $2x^2+5x - 58 = 0$

By quadratic formula

⇒ $x = \frac{-b \pm \sqrt{b^2-4ac} }{2a}$

⇒ $x = \frac{-5 \pm \sqrt{5^2-4(2)(-58)} }{2(2)}$

⇒ $x = \frac{-5 \pm 22.11}{4}$

⇒ $x = \frac{-5 + 22.11}{4} , x = \frac{-5 - 22.11}{4}$ { Since side can't be negative ! }

⇒ $x =4.28$

c) calculate the volume of the box, stating units of you answer

Since x = 4.28 , other sides are

$2x+5=2(4.28)+5=13.56\\x-2=4.28-2=2.28$

We know that volume is given by :

⇒ $length(width)(height)$

⇒ $13.86(4.28)(2.28)$

⇒ $135.25cm^3$

Therefore , volume = $135.25cm^3$ .

7 0

3 years ago

4. Estimate the sum of 9.327 + 5.72 + 4.132 to one decimal place.18.729

ziro4ka [17]

The sum for those numbers is 19.179 NOT 18.729. HOWEVER the Estimation of the sum and the answer for this question is 19.2 because the decimal place you are finding has a number to its right that is greater to that decimal place so you add the one to the decimal place you are finding.

6 0

4 years ago

Read 2 more answers