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damaskus [11]
3 years ago
15

A 2-column table with 7 rows. The first column is labeled x with entries negative 4, negative 3, negative 2, negative 1, 0, 1, 2

. The second column is labeled f of x with entries negative 6, negative 4, negative 1, negative 2, negative 5, negative 8, negative 16. Which is a possible turning point for the continuous function f(x)? (–3, –4) (–2, –1) (0, –5) (1, –8)
Mathematics
1 answer:
Anna [14]3 years ago
5 0
Indeed so first you need to st0p cheating and figure it out 1737
sogxkash
3 years ago
bro go kys your on here too so that either means you yourself is cheating or your just bored and post the same thing on every answer you come across
karen_patroller 001
2 years ago
and you need to stop being a pest and let us have our dang answers karen.
artificialcranapplejuice
2 years ago
ur fun at parties huh
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Using the binomial distribution, it is found that there is a 0.0328 = 3.28% probability that at least 2 of them choose the same quote.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem, we have that:

  • There are 6 students, hence n = 6.
  • There are 20 quotes, hence the probability of each being chosen is p = 1/20 = 0.05.

The probability of one quote being chosen at least two times is given by:

P(X \geq 2) = 1 - P(X < 2)

In which:

P(X < 2) = P(X = 0) + P(X = 1).

Then:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{6,0}.(0.05)^{0}.(0.95)^{6} = 0.7351

P(X = 1) = C_{6,1}.(0.05)^{1}.(0.95)^{5} = 0.2321

Then:

P(X < 2) = P(X = 0) + P(X = 1) = 0.7351 + 0.2321 = 0.9672.

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.9672 = 0.0328

0.0328 = 3.28% probability that at least 2 of them choose the same quote.

More can be learned about the binomial distribution at brainly.com/question/24863377

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