Answer:
a= 40-3b-c/5
a=-10+3b-2c
a=50+2b-3c/14
Step-by-step explanation:
5a+3b+c-(3b+c)=40-(3b+c)
5a=40-3b-c
5a/5=40/5-3b/5-c/5
a= 40-3b-c/5
a-3b+2c-(3b+2c)=-10-(-3b+2c)
a=-10+3b-2c
14a-2b+3c-(-2b+3c)=50-(-2b+3c)
14a=50+2b-3c
14a/14=50/14+2b/14-3c/14
a=50+2b-3c/14
Answer:
the correct answer is 50 really hope this helped :)
Step-by-step explanation:
The distance traveled by the second hand of the clock is 0.471 m.
<h3 />
To calculate the distance the tip of the second hand of the clock travel in 45 seconds, we use the formula below.
<h3>Formula:</h3>
- L = 2πr∅/360.................. Equation 1
<h3> Where: </h3>
- L = distance traveled by the tip of the second hand.
- r = Length of the second hand
- ∅ = angle formed by the second hand of the clock
- π = pie
From the question,
<h3>Given:</h3>
- r = 10 cm = 0.1 m
- ∅ = (360×45/60) = 270°
- π = 3.14
Substitute these values into equation 1
- L = 0.1×2×270×3.14/360
- L = 0.471 cm.
Hence, The distance traveled by the second hand of the clock is 0.471 m
Learn more about distance traveled here: brainly.com/question/4931057
<h3 />
The standard equation of a circle with centre (xc,yc) and radius R is given by
Substituting
centre (xc,yc) = (4,-3)
R=2.5
The equation is therefore
or
(x-4)^2+(y+3)^2=6.25
Answer:
67
Step-by-step explanation:
d(n) = 4n + 2
= 4(5) + 2
=22
t(d(n)) = 3(22) + 1
= 67
