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Usimov [2.4K]
3 years ago
11

The Priority Matrix allows managers to evaluate and prioritize potential initiatives on what two dimensions? Imperatives, quick

wins Ease of implementation, potential returns Time, Difficulty Complexity, commitment Expense, profit potential
Computers and Technology
1 answer:
In-s [12.5K]3 years ago
6 0

Answer:

The answers are Ease of implementation and potential returns.

Explanation:

The priority matrix allows managers to evaluate and prioritize potential initiatives on Ease of implementation and potential returns.

You might be interested in
Sftp uses which mechanism to provide security for authentication and data transfer?
12345 [234]

Sftp uses SSH mechanism to provide security for authentication and data transfer.

<h3>What are SSH known for?</h3>

SSH or Secure Shell is known to be a kind of a network communication protocol that helps two computers to be able to communicate and also  share their data.

Therefore, one can say that Sftp uses SSH mechanism to provide security for authentication and data transfer.

Learn more about  SSH mechanism from

brainly.com/question/13086077

#SPJ12

3 0
2 years ago
Can you answer this question?
patriot [66]

Answer:

To do this you'll need to use malloc to assign memory to the pointers used.  You'll also need to use free to unassign that memory at the end of the program using the free.  Both of these are in stdlib.h.

#include <stdlib.h>

#include <stdio.h>

#define SIZE_X 3

#define SIZE_Y 4

int main(void){

       int **matrix, i, j;

       // allocate the memory

       matrix = (int**)malloc(SIZE_X * sizeof(int*));

       for(i = 0; i < SIZE_X; i++){

               matrix[i] = (int *)malloc(SIZE_Y * sizeof(int));

       }

       // assign the values

       for(i = 0; i < SIZE_X; i++){

               for(j = 0; j < SIZE_Y; j++){

                       matrix[i][j] = SIZE_Y * i + j + 1;

               }

       }

       // print it out

       for(i = 0; i < SIZE_X; i++){

               for(j = 0; j < SIZE_X; j++){

                       printf("%d, %d:  %d\n", i, j, matrix[i][j]);

               }

       }

       // free the memory

       for(i = 0; i < SIZE_X; i++){

               free(matrix[i]);

       }

       free(matrix);

       return 0;

}

3 0
3 years ago
What happens if two functions are defined with the same name, even if they are in different arguments within the same .py files?
yan [13]

Answer:

Following are the code to this question:

def data(a):#defining method data that accepts parameter

   print (a)#print parameter value

def data(b):#defining method data that accepts parameter

   print (b)#print parameter value

x=input("enter value: ")#defining variable x that5 input value from user

print(data(x))#call method data

Output:

enter value: hello..

hello..

None

Explanation:

  • As the above code, it is clear defines that python doesn't support the method overloading because More than one method can't be specified in a python class with the same name and python method arguments have no type.
  • The single argument method may be named using an integer, a series, or a double value, that's why we can say that it is not allowed.
7 0
3 years ago
1. Write a program to prompt the user to enter a single character and respond back whether or not the character is valid dna. 2.
Nina [5.8K]

Answer:

Answer 1:

dna = input("Enter DNA type: ")

dna = dna.upper()

print(dna)

if dna == "A" or dna == "B" or dna == "Z":

   print("valid")

else:

   print("invalid")

Answer 2:

rna = input("Enter DNA type: ")

rna = rna.lower()

print(rna)

if rna == "m" or rna == "t" or rna == "r":

   print("valid")

else:

   print("invalid")

Answer 3:

dnaSquence = input("Enter the DNA sequence: ")

type = "valid"

for char in dnaSquence:

   if char not in ["A", "C", "G", "T"]:

       type = "invalid"

       break

print(type)

Answer 4:

rnaSquence = input("Enter the RNA sequence: ")

type = "valid"

for char in rnaSquence:

   if char not in ["A", "C", "G", "U"]:

       type = "invalid"

       break

print("valid")

Explanation:

There are three types of DNA; Type A, Type B and Type Z.

A DNA sequence consists of; A, C, G and T.

There are three types of RNA; mRNA, tRNA and rRNA.

An RNA sequence consists of; A, C, G and U.

Code Explanations:

Code 1:

dna = input("Enter DNA type: ")

dna = dna.upper()

print(dna)

if dna == "A" or dna == "B" or dna == "Z":

   print("valid")

else:

<em>    print("invalid")</em>

  1. prompts and Takes a single character input
  2. converts the character to upper case
  3. compares the input to the DNA types
  4. Prints "valid" for a valid input else prints "invalid"

Code 2:

rna = input("Enter DNA type: ")

rna = rna.lower()

print(rna)

if rna == "m" or rna == "t" or rna == "r":

   print("valid")

else:

<em>    print("invalid")</em>

<em />

  1. prompts and Takes a single character input
  2. converts the character to lower case
  3. compares the input to the RNA types
  4. Prints "valid" for a valid input else prints "invalid"

Code 3:

Answer 3:

dnaSquence = input("Enter the DNA sequence: ")

type = "valid"

for char in dnaSquence:

   if char not in ["A", "C", "G", "T"]:

       type = "invalid"

       break

print(type)

  1. It prompts for a DNA sequence.
  2. Declares a string variable "type" and initializes type to valid.
  3. The FOR loop checks every character in the DNA sequence.
  4. If the character is not in the list [A, C, G, T] type becomes invalid and the loop breaks and the type "invalid" is printed to the screen.
  5. if all the characters are in the list, then type will remain valid and will be printed to the screen.

Code 4:

rnaSquence = input("Enter the RNA sequence: ")

type = "valid"

for char in rnaSquence:

   if char not in ["A", "C", "G", "U"]:

       type = "invalid"

       break

print("valid")

  1. It prompts for a RNA sequence.
  2. Declares a string variable "type" and initializes type to valid.
  3. The FOR loop checks every character in the RNA sequence.
  4. If the character is not in the list [A, C, G, U] type becomes invalid and the loop breaks and the type "invalid" is printed to the screen.
  5. if all the characters are in the list, then type will remain valid and will be printed to the screen.

7 0
3 years ago
JAVA QUESTION::
allochka39001 [22]

Answer:

3) 44 10 44

Explanation:

Given data

int [] val = { 3, 10, 44 };

The total number of parameters of given array are 3, so total length of array is also 3.

The indexing of array starts with '0', Therefore the <u>indexes</u> of array with length zero are: {0,1,2}

The value of array at index 0 is = 3

similarly

value at index 1 = 10

value at index 2 = 44

Any value of index 'i' of an array is selected using array[i].

Therefore,

val[0] is selecting the value of array located at index '0'.

val[0] = 3

val[2] is selecting the value of array located at index '2'.

val[2] = 44

Finally,

val[0] = val[2]; is copying the value placed at index 2 (44) to value placed at index 0 (3). Hence, the output would be { 44 10 44}. So 3rd option is correct.

 

8 0
4 years ago
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