A string parameter and returns new string with all the letters of the alphabet that are not in the argument string. The letters in the returned string should be in alphabetical order. The implementation should uses a histogram from the histogram function
Explanation:
The below code is written in python :
alphabet = "abcdefghijklmnopqrstuvwxyz"
test_dups = ["zzz","dog","bookkeeper","subdermatoglyphic","subdermatoglyphics"]
test_miss = ["zzz","subdermatoglyphic","the quick brown fox jumps over the lazy dog"]
def histogram(s):
d = dict()
for c in s:
if c not in d:
d[c] = 1
else:
d[c] += 1
return d
def has_duplicates(s):
for v in histogram(s).values():
if v > 1:
return True
return False
def test_dups_loop():
for s in test_dups:
print(s + ':', has_duplicates(s))
def missing_letters(s):
r = list('abcdefghijklmnopqrstuvwxyz')
s = s.lower()
for c in s.lower():
if c in r:
r.remove(c) # the first matching instance
return ''.join(r)
def test_miss_loop():
for s in test_miss:
print(s + ':', missing_letters(s))
def main():
test_dups_loop()
test_miss_loop()
if __name__ == '__main__':
main()
Answer:
The program is as follows:
word = input("Enter a word: ")
if word:
if len(word) <= 4:
word = word[::-1]
else:
word = word[0]+word[1]+word[-2]+word[-1]
print(word)
else:
print('empty!')
Explanation:
This gets input for word from the user
word = input("Enter a word: ")
If input is not empty
if word:
This checks if the length is less than or equal to 4 characters
if len(word) <= 4:
If yes, this reverses the word
word = word[::-1]
If otherwise,
else:
This gets the first, second, second to last two characters
word = word[0]+word[1]+word[-2]+word[-1]
Print the new string
print(word)
Print empty, if input is empty
<em>else:
</em>
<em> print('empty!')</em>
Free space going around the town states
Answer:
A,B,D
A. Allows you to be sure the problem and solution are understood
B. Presents the solution in a manner that is easy to share
C. Is a starting point for all other activities
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