Answers:
B. <span>The x-coordinate of point A is 5.
</span>E. <span>Point A is on the x-axis.
</span>
Explanation:
Any point drawn on the coordinates has the general notation of (x,y).
The given point is (5,0). This means that:
The x-coordinate of the point is 5
The y-coordinate of the point is 0
Now, let's check the place of this point.
The x-coordinate of the point is 5. This means that we will move 5 points to the right of the origin on the x-axis
The y-coordinate of the point is 0. This means that we will not move along the y-axis which means that the point stays on the x-axis.
Now, comparing the deduced results with the given choices, we will find that the correct choices are B and E
Hope this helps :)
By elimination:
y = 3x - 1
y = 2x + 2
Subtract the second equation from the first
0 = x - 1
y = 2x + 2
Subtract the first equation from the second
0 = x - 1
y = x + 3
Subtract the first equation from the second again
0 = x - 1
y = 4
Subtract x from both sides of the first equation
- x = - 1
y = 4
Divide the first equation by (-1)
x = 1
y = 4
<h3>
So, the solution is x = 1 and y = 4 {or: (1, 4)}</h3>
The Lagrangian,
has critical points where its partial derivatives vanish:
tells us 
, so that
Then with 
, we get
and 
tells us
Then there are two critical points, 
. The critical point with the negative 
-coordinates gives the maximum value, 
.
Answer:
<h3>
Sample Answer:<em> </em></h3><h3><em>A linear function has a constant rate of change, while a nonlinear function does not. For a table of values to be linear, the outputs must have a constant rate of change as the inputs increase by 1. On a graph, the function must be a straight line to be linear.</em></h3>
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