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Alenkasestr [34]
3 years ago
15

How do you solve this problem In geometry?

Mathematics
1 answer:
JulsSmile [24]3 years ago
6 0
The 2 smaller triangles are similar.  Thus, y is to z as x is to 4.  You need 3 such ratios to find the 3 unknowns.  Could you try your hand at writing 1 more ratio based upon the illustration?

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Dan was thinking of a number. Dan doubles it and gets an answer of 34.7. What was the original number?
Ksju [112]
347/2 just did it!!! Good luck
3 0
2 years ago
Read 2 more answers
A) What are the null and alternative hypotheses.
e-lub [12.9K]

the answer is C or A. I believe

4 0
2 years ago
ASAP! BRAINLIEST!
nasty-shy [4]

Answer:

The average rate of change from 3 to 6 storms = 0.04

Step-by-step explanation:

Let number of Storms = N

And Predicted Gas Price = P

it is required to find the average rate of change from 3 to 6 storms.

At N = 3 ⇒ P = $2.44

At N = 6 ⇒ P = $2.56

So, the average rate of change = \frac{2.56-2.44}{6-3}=\frac{0.12}{3}=0.04

5 0
2 years ago
6,528 divided by 8 and also 6,349 divided by 9
mote1985 [20]

Answer:

6,528 divided by 8 is 816

6528/8 = 816

6348 divide by 9 is 705.44..... ♾️

7 0
2 years ago
An economy pack of highlighters contains 12 yellow, 6 blue, 4 green, and 3 orange highlighters. An experiment consists of random
Serhud [2]

Answer:

The probability of choosing a blue or yellow highlighter when one yellow highlighter is picked is 17/25.

Step-by-step explanation:

Here, according to the question:

Total number of yellow highlighters  = 12

Total number of blue  highlighters  = 6

Total number of green highlighters  = 4

Total number of orange  highlighters  = 3

So, the total number of highlighters  =  12 + 6 + 4 + 3  = 25

Let E1 : Event of selecting a yellow highlighter.

P(E1)  = \frac{\textrm{Total number of yellow highlighters}}{\textrm{Total Highlighters}}  = \frac{12}{25}

Let E2 : Event of selecting blue or yellow highlighter ONCE yellow highlighter is selected.

So, the total yellow highlighters left after selecting one = 12 -1  = 11

Also, the number of blue highlighter  =  6

So, the TOTAL FAVORABLE options to E2 = 6+ 11 = 17

P(E2)  =

\frac{\textrm{Total number of yellow  + Blue   highlighters}}{\textrm{Total Highlighters}} = \frac{17}{25}

Hence, the probability that a blue or yellow highlighter is selected given that a yellow highlighter is selected is 17/25.

7 0
2 years ago
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