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3 years ago

Is 56 ft, 65 ft, 16 ft a right triangle

Mathematics

2 answers:

Debora [2.8K]3 years ago

7 0

No, it isn't a right triangle.

stira [4]3 years ago

3 0

If there is an angle that is exactly 90 degrees then yes

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Can anyone solve this for me???

Elena-2011 [213]

Answer:

Step-by-step explanation:

It x

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3 years ago

F(x) = -1<br> g(x) = x-4<br> Can you evaluate (gof)(o)? Explain why or why<br> not.

ella [17]

Answer: Yes. (gof)(0) = -5

(gof)(0) means you will find the function of g(f(0)), which means we will find f(0) and plug that value in for x in the function g(x)

We know f(0) is -1, so we can plug -1 into the equation of g(x)

(gof)(0) = (-1) - 4
(gof)(0) = -5

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3 years ago

How much interest would $1500 earn in one day at a rate of 1.75% compounded daily?

soldi70 [24.7K]

Answer:

1526.25 so in one day the interest will have added 26.25

Step-by-step explanation:

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3 years ago

The radius of a semicircle is 3 kilometres. What is the semicircle's perimeter?

alina1380 [7]

Answer:

In terms of Pi: $3\pi + 6$ km

Exact value (rounded): 15.42477 km

Approximated (3.14): 15.42 km

Step-by-step explanation:

Hello!

A semicircle's perimeter can be found using the formula: $P = \pi r + 2r$

We can plug in the values to solve for the perimeter.

<h3>Solve</h3>

$P = \pi r + 2r$
$P = \pi(3)+ 2(3)$
$P = 3\pi + 6$

In terms of Pi, it is $3\pi + 6$ ,

Exact value of Pi, it is 15.42477

Approximation of Pi (3.14), it is = 15.42

6 0

1 year ago

A jumbo crayon is composed of a cylinder with a conical tip. The cylinder is 12 cm tall with a radius of 1.5 cm, and the cone ha

s2008m [1.1K]

Answer:

Part 1) The lateral area of the cone is $LA=2\pi\ cm^{2}$

Part 2) The lateral surface area of the cylinder is $LA=36\pi\ cm^{2}$

Part 3) The surface area of the crayon is $SA=41.50\pi\ cm^{2}$

Step-by-step explanation:

Part 1) Find the lateral area of the cone

The lateral area of the cone is equal to

$LA=\pi rl$

we have

$r=1\ cm$

$l=2\ cm$

substitute

$LA=\pi (1)(2)$

$LA=2\pi\ cm^{2}$

Part 2) Find the lateral surface area of the cylinder

The lateral area of the cylinder is equal to

$LA=2\pi rh$

we have

$r=1.5\ cm$

$h=12\ cm$

substitute

$LA=2\pi (1.5)(12)$

$LA=36\pi\ cm^{2}$

Part 3) Find the surface area of the crayon

The surface area of the crayon is equal to the lateral area of the cone, plus the lateral area of the cylinder, plus the top area of the cylinder plus the bottom base of the crayon

<em>Find the area of the bottom base of the crayon</em>

$A=\pi[r2^{2}-r1^{2}]$