Variations problem Help please
1 answer:
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Answer:
This case has NO solutions.
Step-by-step explanation:
Notice that you are in a case of an obtuse triangle (one of its angles is larger than 90 degrees), the side opposite to the obtuse triangle is shorter than the side adjacent to the angle, so no actual triangle can be formed.
This can be found by simply trying to apply the Law of Sines to solve for the value of angle "B" opposite to side "b":
As shown above, we get an impossible mathematical condition (also call an absurd), since the sine of an angle cannot give a value larger than 1 (one).
Therefore, there is no angle we can find to build a triangle with the given data.
Hi there!
Recall the volume of a pyramid is:
V = 1/3(bh)
We are given the volume and side length of the base. Find the area of the base:
A = s²
A = (5xy²)² = 25x²y⁴
Plug in the solved for base:
125x³y³ = 1/3(25x²y⁴)h
To isolate for h, begin by multiplying both sides by 3:
375x³y³ = (25x²y⁴)h
Divide both sides by 25x²y⁴. Use the following exponent property:
xᵃ / xᵇ = xᵃ⁻ᵇ
Thus:
375x³y³ / 25x²4⁴ = 15x/y.
The height must be equal to: