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Colt1911 [192]
4 years ago
5

Find the average rate of change of the function

Mathematics
2 answers:
max2010maxim [7]4 years ago
3 0
X1 = 4 so sqrt(4) = 2
x2 = 9 so sqrt(9) = 3
3-2 = 1

9-4 = 5

rate of change = 1/5
Darya [45]4 years ago
3 0
To the risk of being redundant

\bf slope = m = \cfrac{rise}{run} \implies 
\cfrac{ f(x_2) - f(x_1)}{ x_2 - x_1}\impliedby 
\begin{array}{llll}
average~rate\\
of~change
\end{array}\\\\
-------------------------------\\\\
f(x)=  \sqrt{x} \qquad 
\begin{cases}
x_1=4\\
x_2=9
\end{cases}\implies \cfrac{f(9)-f(4)}{9-4}\implies \cfrac{\sqrt{9}-\sqrt{4}}{5}
\\\\\\
\cfrac{3-2}{5}\implies \cfrac{1}{5}
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Which inequality will have a dashed boundary line with a shaded area above its graph? 7x − y ≤ 3 x − y ≤ 4 2x − 9y > 2 4x + 7
alexdok [17]
Above the graph

look at them

7x-y <span><</span>3
x-y<span><</span>4
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aswer is 4x+7y>3
5 0
4 years ago
PRS is isosceles with RP RS RQ is drawn such that it bisects PRS What additional fact can be used to prove PRQ SRQ by Sas in ord
SOVA2 [1]

Answer:

\frac{PQR}{SQR}

Step-by-step explanation:

An isosceles triangle has two equal sides and the two opposite angles to the sides to be equal.

Given that; RP = RS, RQ and PS are common,

RP = SQ (opposite sides of parallelogram RPQS)

PQ = RS (opposite sides of parallelogram RPQS)

ΔRPS = ΔQPS (congruence property)

Thus comparing triangles PQR and SQR,

\frac{PQ}{SQ} = \frac{PR}{SR} (similarity property)

<PRS = <PRQ + <SRQ (bisection of included <PRS)

<PQS = <PQR + <SQR (similatity property to <PRS)

\frac{PRQ}{SRQ}  = \frac{SQR}{PQR} (congruence property)

But, SRQ = PQR

So that;

       \frac{PRQ}{SQR}

Therefore by Side-Angle-Side (SAS), the required additional fact is:  \frac{PRQ}{SQR}

8 0
3 years ago
I need help with Two-Step equations. Can I get some.
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