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Natasha_Volkova [10]
3 years ago
5

Can a system of equations have more than one solution

Mathematics
1 answer:
sasho [114]3 years ago
7 0
Yes there could be more than a billion ways to solve a system of equations
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Can someone plss help me with this question!!
Ganezh [65]

Answer: B

1 Newton with a force going right will remain

In D the object wont move

In A the object wont move

In C the object will move left

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3 years ago
128x³y⁴-56x²y²-72x⁴y² by 16x²y
nekit [7.7K]

Answer:

Step-by-step explanation:

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3 0
3 years ago
In a semiconductor manufacturing process, three wafers from a lot are tested. Each wafer is classified as pass or fail. Assume t
Angelina_Jolie [31]

Answer:

P(X = 0) = 0.027

P(X = 1) = 0.189

P(X = 2) = 0.441

P(X = 3)= 0.343

Step-by-step explanation:

The probability mass function P(X = x) is the probability that X happens x times.

When n trials happen, for each x \leq n, the probability mass function is given by:

P(X = x) = pe_{n,x}.p^{x}.(1-p)^{n-x}

In which p is the probability that the event happens.

pe_{n,x}, is the permutation of n elements with x repetitions(when there are multiple events happening(like one passes and two not passing)). It can be calculated by the following formula:

pe_{n,x} = \frac{n!}{x!}

The sum of all P(X=x) must be 1.

In this problem

We have 3 trials, so n = 3

The probability that a wafer pass a test is 0.7, so p = 0.7

Determine the probability mass function of the number of wafers from a lot that pass the test.

P(X = 0) = (0.7)^{0}.(0.3)^{3} = 0.027

P(X = 1) = pe_{3,1}.(0.7).(0.3)^{2} = 0.189

P(X = 2) = pe_{3,2}.(0.7)^{2}.(0.3) = 0.441

P(X = 3) = (0.7)^{3} = 0.343

5 0
4 years ago
If X = 2 inches, Y = 8 inches, W = 4 inches, and Z = 4 inches, what is the area of the object?
max2010maxim [7]

Answer:

C. 63 square inches

4 0
3 years ago
How are volatility and risk related in an investment?
Semenov [28]
The answer is B
hope this helps
5 0
3 years ago
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