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Nimfa-mama [501]
3 years ago
14

The teachers’ edition of a statistics textbook sells for $150, and students’ edition of the book sell for $50 each. which functi

on can be used to find the average cost per book if two teachers’ editions and x students’ editions are purchased?
a. f(x)= 150 50x over 1 x
b. f(x)= 150 50x over 2 x
c. f(x)= 300 50x over 1 x
d. f(x)= 300 50x over 2 x
Mathematics
2 answers:
natima [27]3 years ago
4 0
Its d) f(x)= 300+50x/2+x..............................................................................
Juliette [100K]3 years ago
4 0

Answer:

d

Step-by-step explanation:

Lets have a look at what is given:

Teachers edition of statistics textbook sells for $150

Students edition of statistics textbook sells for $50.

Two teachers and x student books are purchased.

Let f(x) = the average cost per book

Therefore the amount of the teachers textbook cost 2*$150 = $300

and the students texbook costs x*$50= $50x

The average cost per book is:

f(x) = (300+50x)/(x+2)

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elena-14-01-66 [18.8K]
Amount of car loan taken by Scott = $5500
Amount of loan paid back by Scott = $7370
Then
Amount of money paid as interest by Scott = (7370 - 5500) dollars
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Then
Percentage of interest given for the car loan = (1870/5500) * 100
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4 0
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The family of solutions to the differential equation y ′ = −4xy3 is y = 1 √ C + 4x2 . Find the solution that satisfies the initi
slega [8]

Answer:

The correct option is 4

Step-by-step explanation:

The solution is given as

y(x)=\frac{1}{\sqrt{C+4x^2}}

Now for the initial condition the value of C is calculated as

y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(-2)=\frac{1}{\sqrt{C+4(-2)^2}}\\4=\frac{1}{\sqrt{C+4(4)}}\\4=\frac{1}{\sqrt{C+16}}\\16=\frac{1}{C+16}\\C+16=\frac{1}{16}\\C=\frac{1}{16}-16

So the solution is given as

y(x)=\frac{1}{\sqrt{C+4x^2}}\\y(x)=\frac{1}{\sqrt{\frac{1}{16}-16+4x^2}}

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So the correct option is 4

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