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n200080 [17]
3 years ago
14

The rule below shows how the weight in ounces of a kitten depends on its age in weeks. Multiply the age in weeks by 6 and then a

dd 9. If W = weight in ounces and x = age in weeks, which equation expresses the rule above?
A. W(x) = 9(x + 6)
B. W(x) = 6(x + 9)
C. W(x) = 6x + 9
D. W(x) = 9x + 6
Mathematics
1 answer:
viva [34]3 years ago
8 0
The answer for this answer would have to be C. 6 multiplied by weeks(x) then add 9. 
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Functions f(x) and g(x) are shown:
Dennis_Churaev [7]

Answer:

Shifted right 6 units.

Step-by-step explanation:

g can be written as a squared binomial since it is of the form:

x^2+2ax+a^2 which can be written as (x+a)^2.

When comparing the expression to the trinomial just mentioned it should be noted that a is -6. So g can be written as: g(x)=(x-6)^2.

Note: Vertex form of a quadratic is y=a(x-h)^2+k where (h,k) is the vertex.

The vertex of the parent is (0,0) and the vertex of g is (6,0). So the parent has shifted right 6 units to get to where g is located.

8 0
3 years ago
PLEASE help me answer this question!!!!
Elena-2011 [213]

Answer:

\frac{77\pi }{3} cm³

Step-by-step explanation:

The volume (V) of a sphere is calculated as

V = \frac{4}{3}πr³ ( r is the radius )

Here diameter = 4 cm , hence r = 4 ÷ 2 = 2 cm

V = \frac{4}{3}π × 2³ = \frac{4}{3}π × 8 = \frac{32\pi }{3} cm³

Thus

combined volume = \frac{32\pi }{3} + 15π = \frac{32\pi }{3} + \frac{45\pi }{3} = \frac{77\pi }{3} cm³

7 0
3 years ago
Determine wether 16 is the perfect square show proof
enot [183]

Answer:

Therefore, the square root of 16 is an integer, and as a consequence 16 is a perfect square.

As a consequence, 4 is the square root of 16.

Step-by-step explanation:

A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 16 is 4.

Therefore, the square root of 16 is an integer, and as a consequence 16 is a perfect square.

As a consequence, 4 is the square root of 16.

5 0
4 years ago
Factor completely 81x^8-1
marysya [2.9K]

The complete factorized form for the given expression is \left(9 x^{4}+1\right)\left(3 x^{2}+1\right)\left(3 x^{2}-1\right)

<u>Step-by-step explanation:</u>

Step 1: Given expression:

              81 x^{8}-1

Step 2: Trying to factor as a Difference of Squares

Factoring 81 x^{8}-1

As we know the theory that the difference of two perfect squares, A^{2}-B^{2}  can be factored into (A+B) (A-B)

from this, when analysing, 81 is the square of 9, x^{8} is the square of x^{4}. Hence, we can write the given expression as,

            \left(9 x^{4}\right)^{2}-1^{2}

By using the theory, we get

           \left(9 x^{4}+1\right)\left(9 x^{4}-1\right)

Again, we can further factorise the term \left(9 x^{4}-1\right)

9 x^{4} is the square of 3 x^{2}. Therefore, it can be expressed as below

           \left(3 x^{2}+1\right)\left(3 x^{2}-1\right)

Now, we can not factorise further the term \left(3 x^{2}-1\right). Because it will come as \sqrt{3} x (3 is not a square term). Thereby concluding that the complete factorisation for the given expression is \left(9 x^{4}+1\right)\left(3 x^{2}+1\right)\left(3 x^{2}-1\right)

8 0
4 years ago
Chile anyways so-
fredd [130]

Answer:

Chile anyways so-

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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