Line AB contains points A(4, 5) and B(9,7). What is the slope of AB?

Mathematics

2 answers:

vlabodo [156]2 years ago

7 0

Answer:

2/5

Step-by-step explanation:

We can find the slope of a line given two points by using

m =(y2-y1)/(x2-x1)

= (7-5)/(9-4)

= 2/5

Vikki [24]2 years ago

3 0

Answer:

2/5

Step-by-step explanation:

We can find the slope of a line given two points by using

m =(y2-y1)/(x2-x1)

= (7-5)/(9-4)

= 2/5

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❗️❗️❗️Find the length of side x in simplest radical form with a rational denominator.❗️❗️❗️

tiny-mole [99]

Answer:

$x=\frac{\sqrt{14} }{2}$

Step-by-step explanation:

Notice that you are given an isosceles right-angle triangle to solve, since each of its two acute angles measures $45^o$ . Then such means that the sides opposite to these acute angles (the so called "legs" of this right angle triangle) must also be of the same length (x).

We can then use the Pythagorean theorem that relates the square of the hypotenuse to the addition of the squares of the triangles legs:

$(\sqrt{7})^2=x^2+x^2\\7=2\,x^2\\x^2=\frac{7}{2} \\x=+/-\sqrt{\frac{7}{2}} \\x=+/-\frac{\sqrt{14} }{2}$

We use just the positive root, since we are looking for an actual length. then, the requested side is:

$x=\frac{\sqrt{14} }{2}$

6 0

2 years ago

What is y=3x^2-2 in vertex form

Nata [24]

$\bf \qquad \qquad \textit{parabola vertex form}
\\\\\\
y=a(x-{{ h}})^2+{{ k}}\\
x=a(y-{{ k}})^2+{{ h}}\qquad\qquad vertex\ ({{ h}},{{ k}})\\\\
-----------------------------\\\\
y=3x^2-2\iff y = 3(x-0)^2-2$