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2 years ago

Write an equation whose graph is a line perpendicular to the graph of x = -7 and which

Mathematics

1 answer:

Travka [436]2 years ago

3 0

Answer:

y = 1

They will pass through each other perpendicular, also you can look up graph in chrome and use a free graph.

Step-by-step explanation:

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Order: give Ceclor (cefaclor) 250 mg PO every 8 hours.

irinina [24]

Hello!

The answer is: 15 mL

Why?

From the statement we have that 250 mg need to be given every 8 hours, we can calculate how many mg will be given each day (24 hours):

$\frac{24Hours}{8Hours} = 3$

So,

$3*250mg=750mg$ a day

We also know that there are 50 mg cefaclor every 1mL,

So, to know how many mL will be given with 750mg, we just need to divide it by 50

$\frac{750}{50} = 15$

Therefore,

15mL or 750 mg of cefaclor will be given each day.

Have a nice day!

8 0

2 years ago

What type of angle is created by the intersection of two perpendicular lines rats or line segment

zmey [24]

It should be a right angle (90º).

6 0

3 years ago

Find the centroid for an area defined by the equations y = x² + 3 and y = - (x – 2)² + 7

sergeinik [125]

First we need to find where the 2 graphs intercept.

x^2 + 3 = - (x^2 - 4x + 4) + 7
x^2 + 3 = -x^2 + 4x + 3
2x^2 - 4x = 0
2x(x - 2)

x = 0 , 2. are x coordinates of the 2 intercepts.

6 0

2 years ago

Please help FAST I need the answer along with you explaining the steps so I can get it thanks! I’ll give Brainlist also!

kupik [55]

Answer:

The equation of required line is: $\mathbf{5x-8y+34=0}$

Step-by-step explanation:

We need to write equation in the form Ax+By+C=0 of the line parallel to $5x-8y+12=0$ and through the point (-2,3)

First we need to find slope and y-intercept of the required line.

Using equation of line $5x-8y+12=0$ to find slope.

Since the given line and required lines are parallel there slope is same.

Writing equation in slope intercept form: $y=mx+b$ where m is slope.

$5x-8y+12=0 \\-8y=-5x-12\\\frac{-8y}{-8y}=\frac{-5x}{-8}-\frac{12}{-8}\\y=\frac{5}{8}x+\frac{3}{4}$

So, the slope m = 5/8

The slope of required line is $m=\frac{5}{8}$

Now finding y-intercept using slope $m=\frac{5}{8}$ and point(-2,3)

$y=mx+b\\3=\frac{5}{8}(-2)+b\\3=\frac{-5}{4}+b\\b=3+\frac{5}{4}\\b=\frac{3*4+5}{4}\\b=\frac{12+5}{4}\\b=\frac{17}{4}$

So, the equation of required line having slope $m=\frac{5}{8}$ and y-intercept $b=\frac{17}{4}$

$y=mx+b\\y=\frac{5}{8}x+\frac{17}{4}\\y=\frac{5x+17*2}{8}\\y= \frac{5x+34}{8} \\8y=5x+34\\5x-8y+34=0$

So, The equation of required line is: $\mathbf{5x-8y+34=0}$

3 0

2 years ago

Simple interest on a bank loan can be calculated by multiplying the principal times the interest rate times the time. In the for

prisoha [69]

I = interest/simple interest

So your answer is D.

5 0

2 years ago

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