A=P(1+rt)
A/P=1+rt
A/P-1=rt
AP-P/Pr = t
A-1/r=t
If a,b,c are the 3 positive integers
1/a +1/b +1/c > 6/abc
(bc+ac+ab)/abc >6/abc so
(bc+ac+ab)>6
The lowest positive integers that are different are 1,2,3 so the lowest value that (bc+ac+ab) could have is 1•2+2•3+1•3=2+6+3= 11 therefore
1/a +1/b +1/c > 6/abc is true
Answer:
3
Step-by-step explanation:
Here is the set up:
(1/4)/2 = (9/4)/y
Solve for y.