Step-by-step explanation:
step 1. the cube root is also to the 1/3 power
step 2. (27a^3b^7)^(1/3) = (3*3*3*a*a*a*b*b*b*b*b*b*b)^(1/3)
step 3. a third root: 3 factors in the root comes "out" of the root as 1
step 4. 3ab*b(b)^(1/3) = 3ab^2(b)^(1/3).
Answer:
1) AD=BC(corresponding parts of congruent triangles)
2)The value of x and y are 65 ° and 77.5° respectively
Step-by-step explanation:
1)
Given : AD||BC
AC bisects BD
So, AE=EC and BE=ED
We need to prove AD = BC
In ΔAED and ΔBEC
AE=EC (Given)
( Vertically opposite angles)
BE=ED (Given)
So, ΔAED ≅ ΔBEC (By SAS)
So, AD=BC(corresponding parts of congruent triangles)
Hence Proved
2)
Refer the attached figure

In ΔDBC
BC=DC (Given)
So,
(Opposite angles of equal sides are equal)
So,
So,
(Angle sum property)
x+x+50=180
2x+50=180
2x=130
x=65
So,
Now,

So,
In ΔABD
AB = BD (Given)
So,
(Opposite angles of equal sides are equal)
So,
So,
(Angle Sum property)
y+y+25=180
2y=180-25
2y=155
y=77.5
So, The value of x and y are 65 ° and 77.5° respectively
Answer:
$0.1966666
Step-by-step explanation:


To the risk of sounding redundant,

and surely you'd know what that is.