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grandymaker [24]
3 years ago
9

A six-sided die is rolled. What is the probability that either a 1, 2, or 3 is rolled?

Mathematics
1 answer:
Inga [223]3 years ago
3 0

Answer:

1/2 I think

Step-by-step explanation:

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Solve for W
umka2103 [35]

In this equation w = -1.1

In order to find this, get all w values to the right side and all numbers to the left side.

-2.27 + 9.1w + 1.3w = -3.4w - 17.45 ----> combine like terms

-2.27 + 10.4w = -3.4w - 17.45 ----> add 3.4w to both sides

-2.27 + 13.8w = -17.45 ----> add 2.27 to both sides

13.8w = -15.18 -----> divide both sides by 13.8

w = -1.1

4 0
3 years ago
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ABCD FECG
MariettaO [177]

Answer:

x=12

Step-by-step explanation:

7 0
3 years ago
A circle with a radius of 10 inches is placed inside a square with a side length of 20 inches. Find the probability that a dart
melamori03 [73]

Answer:

The correct answer is last option 78.5%

Step-by-step explanation:

Points to remember

Area of circle = πr²

Where r is the radius of circle

Area of square = a²

Where 'a' is the side length of square

<u>To find the area of circle</u>

Here r = 10 cinches

Area =  πr²

 =  3.14 * 10²

 = 3.14 * 100 = 314

<u>To find the area of square</u>

Here a = 20 inches

Area = a²

 = 20²

 = 400

<u>To find the probability percentage</u>

Probability = area of circle/Area of square

 = (314/400)*100

 78.5 %

7 0
3 years ago
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Write <br>(6b)^2 without exponents
Nikolay [14]
Squaring a number means you're multiplying the number by itself. This would mean (6b)^2 = (6b)(6b).
4 0
3 years ago
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Give the properties for the equation -2x 2 - y + 10x - 7 = 0.
Sladkaya [172]

Given:

The quadratic equation is

-2x^2-y+10x-7=0

To find:

The vertex of the given quadratic equation.

Solution:

If a quadratic function is f(x)=ax^2+bx+c, then

Vertex=\left(\dfrac{-b}{2a},f(\dfrac{-b}{2a})\right)

We have,

-2x^2-y+10x-7=0

It can be written as

-2x^2+10x-7=y

y=-2x^2+10x-7           ...(i)

Here, a=-2,b=10,c=-7.

\dfrac{-b}{2a}=\dfrac{-10}{2(-2)}

\dfrac{-b}{2a}=\dfrac{-10}{-4}

\dfrac{-b}{2a}=\dfrac{5}{2}

Putting x=\dfrac{5}{2} in (i), we get

y=-2(\dfrac{5}{2})^2+10(\dfrac{5}{2})-7

y=-2(\dfrac{25}{4})+\dfrac{50}{2}-7

y=\dfrac{-50}{4}+25-7

y=\dfrac{-25}{2}+18

On further simplification, we get

y=\dfrac{-25+36}{2}

y=\dfrac{11}{2}

So, the vertex of the given quadratic equation is \left(\dfrac{5}{2},\dfrac{11}{2}\right).

Therefore, the correct option is A.

3 0
3 years ago
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