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prohojiy [21]
3 years ago
14

A bin contains 72 light bulbs of which 10 are defective. If 5 light bulbs are randomly selected from the bin with replacement, f

ind the probability that all the bulbs selected are good ones. Round to the nearest thousandth if necessary. (Hint: sampling with replacement = independent events)
Mathematics
1 answer:
Serhud [2]3 years ago
7 0

Answer:

0.4735

Step-by-step explanation:

10 defective, 62 not defective

P(good) = 62/72 = 31/36

All 5 good:

(31/36)⁵ = 0.4734738145

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Find the product of (x − 5)2. (1 point) Group of answer choices x2 + 10x + 25 x2 − 10x + 25 x2 − 25 x2 + 25
Anuta_ua [19.1K]

Answer:

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Step-by-step explanation:

Hello!

Expand the square using the Distributive Property.

<h3>Expand</h3>
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Distributive x - 5 to each factor

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The answer is x^2 - 10x + 25.

We can also use a special binomial product formula.

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2 years ago
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mezya [45]

Answer:

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Step-by-step explanation:

They are supplementary, so they add to 180. 180 - 124 = 56.

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