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jok3333 [9.3K]
3 years ago
7

Consider the following functions.

Mathematics
1 answer:
Alchen [17]3 years ago
8 0
Well this kinda hard I’ll work it out
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1. Solve using long division.
Ann [662]

Answer:

9x^2 - 3x - 2,  R -7.

Step-by-step explanation:

x - 5) 9x^3 - 48x^2 + 13x + 3(9x^2 - 3x - 2 <---- Quotient.

        9x^3 - 45x^2

                  - 3x^2 + 13x

                   -3x^2 + 15x

                                -2x + 3

                                -2x + 10

                                          -7 <----- Remainder

5 0
3 years ago
Write a statistical question based on number of hours spent with friends per week
dlinn [17]
Compare the time spent with friends to the overall hours you’ve spent on working this week. How much of your total work was it?
4 0
3 years ago
Read 2 more answers
EXAMPLE 5 Find the maximum value of the function f(x, y, z) = x + 2y + 9z on the curve of intersection of the plane x − y + z =
geniusboy [140]

The Lagrangian,

L(x,y,z,\lambda,\mu)=x+2y+9z-\lambda(x-y+z-1)-\mu(x^2+y^2-1)

has critical points where its partial derivatives vanish:

L_x=1-\lambda-2\mu x=0

L_y=2+\lambda-2\mu y=0

L_z=9-\lambda=0

L_\lambda=x-y+z-1=0

L_\mu=x^2+y^2-1=0

L_z=0 tells us \lambda=9, so that

L_x=0\implies-8-2\mu x=0\implies x=-\dfrac4\mu

L_y=0\implies11-2\mu y=0\implies y=\dfrac{11}{2\mu}

Then with L_\mu=0, we get

x^2+y^2=\dfrac{16}{\mu^2}+\dfrac{121}{4\mu^2}=1\implies\mu=\pm\dfrac{\sqrt{185}}2

and L_\lambda=0 tells us

x-y+z=-\dfrac4\mu-\dfrac{11}{2\mu}+z=1\implies z=1+\dfrac{19}{2\mu}

Then there are two critical points, \left(\pm\frac8{\sqrt{185}},\mp\frac{11}{\sqrt{185}},1\pm\frac{19}{\sqrt{185}}\right). The critical point with the negative x-coordinates gives the maximum value, 9+\sqrt{185}.

8 0
3 years ago
How do you write the equation 4x + 2y = 16 in function form? Please answer with an explanation!
kramer
F(x)=-2x+8 This is because f(x) is the same as writing y so therefore you have to change the equation to 4x+2y=16 so you have Y=-2x+8
3 0
3 years ago
At a track meet 2/7of the 756 competing athletes are sophomores. How many of the competing
kkurt [141]

Answer:

D

Step-by-step explanation:

700/7= 100

100*2= 200

200+ (756-700)= 256

256 closest to 216 than to 204 or any other answer.

5 0
3 years ago
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