Answer:
16%
Step-by-step explanation:
The mean is $15 and the standar deviation is $3.
mean = 15 and SD = 3
We need to find percentage less than 12 per hour
P(x<12)= P(x=12)
to find P(x=12) we find z-score
Now use z-score table . z-score = 0.1587
P(x=12)=0.1587
To get percentage we multiply by 100
0.1587 * 100 = 15.87 = 16%
Step-by-step explanation:
Ok. First of all, we need to follow the order of operations: Parentheses, Exponents, Multiplication, Division, Addition, Subtraction. We don't have any parentheses, exponents, or division to resolve, so you can skip those. So now you have: Multiplication, Addition, and Subtraction. We have multiplication in each term, but each term is fully simplified, so we have Addition and Subtraction left.
With that out of the way, let's go ahead and rearrange this equation so it is easier to solve. (<em>Note: we can only rearrange terms that are positive because subtraction is not commutative. But we can turn negative terms into "positive" terms by the method shown below.</em>)
4a - 7b + 2ab - a + b
4a + (-7b) + 2ab + (-a) + b (<em>Now the terms are all positive, so we can rearrange them, but they still have the same value.</em>)
4a + (-a) + 2ab + (-7b) + b
3a + 2ab + 7b
And there we go. Our answer is fully simplified. If you can understand this, you'll be able to simplify without isolating and rearranging the terms each time.
Hopefully this was helpful and not confusing.
Answer:
1/3
Step-by-step explanation:
since you're finding the parallel it would have the same slope since it is parallel and since this equation is already in slope-intercept form, you can see that 1/3 is the slope
Answer:
The proportions differ from those reported in the survey.
Step-by-step explanation:
The Chi-square goodness of fit test would be used to determine whether the proportions differ from those reported in the survey.
The hypothesis for the test can be defined as follows:
<em>H</em>₀: The proportions does not differ from those reported in the survey.
<em>Hₐ</em>: The proportions differ from those reported in the survey.
Assume that the significance level of the test is, α = 0.01.
The Chi-square test statistic is given by:
Consider the Excel sheet provided.
The Chi-square test statistic value is 191.32.
The <em>p</em>-value of the test is:
The <em>p</em>-value of the test is very small. The null hypothesis will be rejected at 1% level of significance.
Thus, concluding that the proportions differ from those reported in the survey.
