All categories

3 years ago

HELP!!! THIS IS DUE AT 11:59!

Mathematics

1 answer:

Misha Larkins [42]3 years ago

3 0

Answer:

1. x = 22

2. x = 38

3. x = 24

Step-by-step explanation:

Uhhhhhh

You might be interested in

13, 5, 4, 9, 7, 14, 4 The deviations are _____.

fenix001 [56]

Answer:

B."5, -3, -4, 1, -1, 6, -4"

Step-by-step explanation:

We are given that

13,5,4,9,7,14,4

We have to find the deviation.

Mean= $\frac{sum\;of\;data}{total\;number\;of\;data}$

Using the formula

$Mean,\mu=\frac{13+5+4+9+7+14+4}{7}$

$Mean,\mu=\frac{56}{7}=8$

Deviation= $x_i-\mu$

$x_i-\mu$

13 5

5 -3

4 - 4

9 1

7 -1

14 6

4 - 4

Hence, option B is correct.

7 0

3 years ago

Describe how to use a tens fact to find the difference for 15-8

arlik [135]

When you use a tens fact you round to the nearest ten and 15-8=7. The nearest ten to seven is 10
Answer:10

5 0

3 years ago

Let X and Y be discrete random variables. Let E[X] and var[X] be the expected value and variance, respectively, of a random vari

Ulleksa [173]

Answer:

(a) $E[X+Y]=E[X]+E[Y]$

(b) $Var(X+Y)=Var(X)+Var(Y)$

Step-by-step explanation:

Let X and Y be discrete random variables and E(X) and Var(X) are the Expected Values and Variance of X respectively.

(a)We want to show that E[X + Y ] = E[X] + E[Y ].

When we have two random variables instead of one, we consider their joint distribution function.

For a function f(X,Y) of discrete variables X and Y, we can define

$E[f(X,Y)]=\sum_{x,y}f(x,y)\cdot P(X=x, Y=y).$

Since f(X,Y)=X+Y

$E[X+Y]=\sum_{x,y}(x+y)P(X=x,Y=y)\\=\sum_{x,y}xP(X=x,Y=y)+\sum_{x,y}yP(X=x,Y=y).$

Let us look at the first of these sums.

$\sum_{x,y}xP(X=x,Y=y)\\=\sum_{x}x\sum_{y}P(X=x,Y=y)\\\text{Taking Marginal distribution of x}\\=\sum_{x}xP(X=x)=E[X].$

Similarly,

$\sum_{x,y}yP(X=x,Y=y)\\=\sum_{y}y\sum_{x}P(X=x,Y=y)\\\text{Taking Marginal distribution of y}\\=\sum_{y}yP(Y=y)=E[Y].$

Combining these two gives the formula:

$\sum_{x,y}xP(X=x,Y=y)+\sum_{x,y}yP(X=x,Y=y) =E(X)+E(Y)$

Therefore:

$E[X+Y]=E[X]+E[Y] \text{ as required.}$

(b)We want to show that if X and Y are independent random variables, then:

$Var(X+Y)=Var(X)+Var(Y)$

By definition of Variance, we have that:

$Var(X+Y)=E(X+Y-E[X+Y]^2)$

$=E[(X-\mu_X +Y- \mu_Y)^2]\\=E[(X-\mu_X)^2 +(Y- \mu_Y)^2+2(X-\mu_X)(Y- \mu_Y)]\\$Since we have shown that expectation is linear$\\=E(X-\mu_X)^2 +E(Y- \mu_Y)^2+2E(X-\mu_X)(Y- \mu_Y)]\\=E[(X-E(X)]^2 +E[Y- E(Y)]^2+2Cov (X,Y)$

Since X and Y are independent, Cov(X,Y)=0

$=Var(X)+Var(Y)$

Therefore as required:

$Var(X+Y)=Var(X)+Var(Y)$

7 0

3 years ago

I WILL AWARD BRAINLIST PLS SOLVE

Ivanshal [37]

Answer:

Ah yes rsm.

Anyways, AB is parallel to DE so 72= angle BDE. So BDE+2x+2x=180

72+4x=180

108=4x

x=27

3 0

3 years ago

1) त्रिभुज LOK को क्षेत्रफल पत्ता लगाउनुहोस् । जहाँ

siniylev [52]

Answer:

hope this helps you.keep it up..

7 0

2 years ago