3 years ago

Which of the following statements is not true about the function shown above?

Mathematics

1 answer:

Studentka2010 [4]3 years ago

8 0

Answer A would the one that's false

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Please help?!

Ugo [173]

draw a rectangle around it:

the widest part is from about -3 to 2 which is 5 units wide

height is from 3 to -4, which is 7 units

5*7 = 35

the top and bottom are angled so you can subtract a little for that

so I would estimate around 32 square units

7 0

4 years ago

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If the number of users tripled every year since 2001, and there were 3 million users in 2005, how many were there in 2004?

otez555 [7]

Divid it by three and you should get it

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3 years ago

= Homework: Special Right Triangles (8.2)

lubasha [3.4K]

rechecking this answer with your lecturer. Tq

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2 years ago

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9(5x) need help asap

dexar [7]

Answer:

45x happy to help ya :)

Step-by-step explanation:

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3 years ago

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Write the general polynomial p(x) if its only zeros are 1 4 and -3 with multiplicites 3 2 and 1 respectively what is the degree

kompoz [17]

Answer:

The 6th degree polynomial is $p(x) = (x-1)^3(x-4)^2(x+3)$

Step-by-step explanation:

Zeros of a function:

Given a polynomial f(x), this polynomial has roots $x_{1}, x_{2}, x_{n}$ such that it can be written as: $a(x - x_{1})*(x - x_{2})*...*(x-x_n)$ , in which a is the leading coefficient.

Zero 1 with multiplicity 3.

$p(x) = (x-1)^3$

Zero 4 with multiplicity 2.

Considering also the zero 1 with multiplicity 3.

$p(x) = (x-1)^3(x-4)^2$

Zero -3 with multiplicity 1:

Considering the previous zeros:

$p(x) = (x-1)^3(x-4)^2(x-(-3)) = (x-1)^3(x-4)^2(x+3)$

Degree is the multiplication of the multiplicities of the zeros. So

3*2*1 = 6

The 6th degree polynomial is $p(x) = (x-1)^3(x-4)^2(x+3)$

8 0

3 years ago