Answer:
The golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of  .
.
Step-by-step explanation:
The formula from the maximum distance of a projectile with initial height h=0, is:

Where  is the initial velocity.
 is the initial velocity.
In the closed interval method, the first step is to find the values of the function in the critical points in the interval which is ![[0, \pi/2]](https://tex.z-dn.net/?f=%5B0%2C%20%5Cpi%2F2%5D) . The critical  points of the function are those who make
. The critical  points of the function are those who make  :
:


The critical value inside the interval is  .
.

The second step is to find the values of the function at the endpoints of the interval:

The biggest value of f is gived by  , therefore
, therefore  is the absolute maximum.
 is the absolute maximum.
In the context of the problem, the golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of  .
.
 
        
             
        
        
        
Answer:
B
Step-by-step explanation:
Got it right on edge. mark me brainliest please
 
        
             
        
        
        
Answer:
I likr=e the Story 12
Step-by-step explanation:
I really like how they jump and 1+1=2 right or is it 3???
Hmmm...
 
        
             
        
        
        
Answer:
-25
Step-by-step explanation:
Essentially, y is your output and x is your input.
Here's your base equation: y = 2x + 5
Knowing the information above, let's plug it in:
-45 = 2x + 5
(Subtract 5 from both sides)
-50 = 2x
(Divide both sides by 2 to isolate x)
-25 = x
And there you go.
 
        
                    
             
        
        
        
add Them all together and divide by the largest
Step-by-step explanation:hope it helps