Answer:6018
Step-by-step explanation:
Given Sequence
It represent an A.P. with
first term 
common difference 
So sum of 51 term
![S_n=\frac{n}{2}[2a+(n-1)d]](https://tex.z-dn.net/?f=S_n%3D%5Cfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D)
![S_{51}=\frac{51}{2}\times [2\times (-282)+(51-1)16]](https://tex.z-dn.net/?f=S_%7B51%7D%3D%5Cfrac%7B51%7D%7B2%7D%5Ctimes%20%5B2%5Ctimes%20%28-282%29%2B%2851-1%2916%5D)
![S_{51}=\frac{51}{2}\times [-564+800]](https://tex.z-dn.net/?f=S_%7B51%7D%3D%5Cfrac%7B51%7D%7B2%7D%5Ctimes%20%5B-564%2B800%5D)
![S_{51}=\frac{51}{2}\times [236]](https://tex.z-dn.net/?f=S_%7B51%7D%3D%5Cfrac%7B51%7D%7B2%7D%5Ctimes%20%5B236%5D)
Answer:
y=14
Step-by-step explanation:
Since this is an isosceles triangle due to opposite sides being congruent, the base angles would also be congruent.
plug in 25 in 2x and you would get 50°
Since the sum of a triangle is 180° you could set up an equation 
Then, add 50+50=100+10=110
then you would then have 
subtract 110 from 180, leaving you with 70
then divide and you would get 14
Check:
5(14)+10+50+50= 180
The points at which a quadratic equation intersects the x-axis are referred to as x intercepts or zeros or roots of quadratic equation
Given :
The points at which a quadratic equation intersects the x-axis
The points at which the any quadratic equation crosses or touches the x axis are called as x intercepts.
At x intercepts the value of y is 0.
So , the points at which a quadratic equation intersects the x-axis is also called as zeros or roots of the quadratic equation .
The points at which a quadratic equation intersects the x-axis are referred to as x intercepts or zeros or roots of quadratic equation
Learn more : brainly.com/question/9055752
Answer:
420
Step-by-step explanation:
The equation of the line that is parallel to the line whose equation is 3x-2y=7 would be y = 3/2x + b, in which b can be any real number.
How are parallel straight lines related?
Parallel lines have the same slope since the slope is like a measure of steepness and since parallel lines are of the same steepness, thus, are of the same slope.
We have been given a parallel line with has equation
3x-2y=7
In order to solve this, the slope of the original line.
3x - 2y = 7
-2y = -3x + 7
y = 3/2x - 7/2
thus its slope is 3/2.
thus, the slope of the needed line is 3/2 too.
we know that any line that is parallel to that would have this slope.
So anything is written in the form:
y = 3/2x + b
The equation of the line that is parallel to the line whose equation is 3x-2y=7 would be y = 3/2x + b, in which b can be any real number.
Learn more about parallel lines here:
brainly.com/question/13857011
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