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arsen [322]
2 years ago
7

Under certain conditions, the number of bacteria present in a colony is approximated by f(t) = Age 0.023t, where t is in minutes

. If A = 2,700,000, find the number of bacteria present at 5 minutes, 10 minutes, and 60 minutes.
Mathematics
1 answer:
AleksandrR [38]2 years ago
8 0

Answer:

  • 5 min: 3,029,058
  • 10 min: 3,398,220
  • 60 min: 10,732,234

Step-by-step explanation:

The given function is evaluated by substituting the given values of t. This requires using the exponential function of your calculator with a base of 'e'. Many calculators have that value built in, or have an e^x function (often associated with the Ln function).

__

<h3>5 minutes</h3>

The number of bacteria present after 5 minutes is about ...

  f(5) = 2.7×10^6×e^(0.023×5) ≈ 3,029,058

<h3>10 minutes</h3>

The number of bacteria present after 10 minutes is about ...

  f(10) = 2.7×10^6×e^(0.023×10) ≈ 3,398,220

<h3>60 minutes</h3>

The number of bacteria present after 60 minutes is about ...

  f(60) = 2.7×10^6×e^(0.023×60) ≈ 10,732,234

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6 0
3 years ago
Given: ⅓ (18x + 27) = 81 Prove: x = 12
sasho [114]

Answer:

Firstly, rewrite the equation:

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Substitute x for the given number of it's supposed equivalent.

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⅓ (18(12) + 27) = 81

Solve using PEMDAS and simplify what is in the parenthesis first. Then, multiply.

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AfilCa [17]

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Step-by-step explanation:

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The final result is: no solution.
7 0
3 years ago
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