Under certain conditions, the number of bacteria present in a colony is approximated by f(t) = Age 0.023t, where t is in minutes
1 answer:
Answer:
- 5 min: 3,029,058
- 10 min: 3,398,220
- 60 min: 10,732,234
Step-by-step explanation:
The given function is evaluated by substituting the given values of t. This requires using the exponential function of your calculator with a base of 'e'. Many calculators have that value built in, or have an e^x function (often associated with the Ln function).
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<h3>5 minutes</h3>The number of bacteria present after 5 minutes is about ...
f(5) = 2.7×10^6×e^(0.023×5) ≈ 3,029,058
<h3>10 minutes</h3>The number of bacteria present after 10 minutes is about ...
f(10) = 2.7×10^6×e^(0.023×10) ≈ 3,398,220
<h3>60 minutes</h3>The number of bacteria present after 60 minutes is about ...
f(60) = 2.7×10^6×e^(0.023×60) ≈ 10,732,234
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Answer:
30th percentile:109
90th percentile: 188
Step-by-step explanation:
The given data set is:
129, 113, 200, 100, 105, 132, 100, 176, 146, 152
We arrange the data set in ascending order to obtain;
Array=
The 30th percentile is located at
-th position, where n=10 is the number of items in the data set
This implies that the 30th percentile is at the 3rd position.
Since 3 is an integer, the 30th percentile is the average of the 3rd and 4th occurrence in the array;
This implies that the 30th percentile =
The 90th percentile is located at
-th position, where n=10 is the number of items in the data set
This implies that the 90th percentile is at the 9th position.
Since 9 is an integer, the 90th percentile is the average of the 9th and 10th occurrence in the array;
This implies that the 90th percentile =