On which interval are both the sine and cosine functions increasing?

Can someone help me out. Its not much with this question.<br> http://prntscr.com/houceo

Lena [83]

If you look at the graph, there's only one line? what the dickens happen to the graph of the other equation?

well, it turns out that, 2y = -2x + 2, is really just 2( y) = 2(-x + 1), if you divide both sides by 2, the 2 goes poof, and the second equation looks exactly just like the first one.

that means the graph for the second equation, is exactly the same as the first one, so there are two lines in that picture, it's just that one line is pancaked on top of the other. Meaning the system has "infinitely many solutions", pretty much every single point in the graph.

the points are coinciding with each other, they're just pancaked on one another, is coincident.

the system has at least one solution, it really has an infinite number, but it as a least one though, is consistent.

so that makes the system consistent and coincident.

4 0

3 years ago

The number of gallons of gas in the tanks plus 7 more adds up to 12 gallons

Sunny_sXe [5.5K]

If the question is asking how much gas there was before it would be 5 gallons. Im confused on what you want for the answer.

7 0

3 years ago

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Here are three similar cuboids, A, B and C.

gregori [183]

The answer is bc cause you multiply 12 x 2= 24

3 0

3 years ago

Anyone help???<br> Thank you<br> need it in 3 min

den301095 [7]

Answer:

$40.352

Step-by-step explanation:

7 0

3 years ago

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A simple random sample of 25 filtered 100mm cigarettes is obtained, and the tar content of each cigarette is measured. The sampl

zaharov [31]

Answer:

A) -1.40

B) -1.71

C) 0.0872

Step-by-step explanation:

Sample size = n = 25

Sample mean = x = 20.2 mg

Sample standard deviation = s = 3.21 mg

Claim: Sample mean is less than 21.1 mg

So, u = 21.1

Null Hypothesis: u ≥ 21.1 mg

Alternate Hypothesis? u < 21.1 mg

Since we have the sample standard deviation, we will use the t-distribution to answer this question

Part A) t-test statistic

The formula to calculate the t-test statistic is:

$t=\frac{x-u}{\frac{s}{\sqrt{n} } }$

Using the values, we get:

$t=\frac{20.2-21.1}{\frac{3.21}{\sqrt{25} } }\\\\ t=-1.40$

Thus, the value of t-test statistic is -1.40

Part B) Critical Value

In order to calculate the critical value we need the value of significance level and the number of degrees of freedom.

Degrees of freedom = df = n -1 = 25 - 1 = 24

Using t-table or t-critical value calculator for significance level 0.05 and 24 df the value comes out to be:

t-critical = -1.71

Since this is a left tailed test, we have considered the negative t-critical value. Rejection region will be the values less than -1.71 i.e. values which lie to left of -1.71

Part C) P-value

In order to calculate the P-value we need the t-score which we calculated in part A and the degrees of freedom.

Using the t-table or p value calculator the p value for t score of -1.40 and df 24 comes out to be:

p-value = 0.0872

Conclusion:

Since the p-value is larger than the significance level, we fail to reject the claim.

Also the test-statistic does not lie in the rejection region, so another hint that we cannot reject the claim.

Thus, no conclusion can be drawn about the effectiveness of the filters using these tests.

3 0

3 years ago