Answer: it’s the first one
Step-by-step explanation:
If <em>a</em> is fixed and <em>b</em>,<em>c</em> are unknowns then the equation <em>b</em>+<em>c</em>=10-<em>a</em> has 11-<em>a</em> solutions. They are pairs (b,c): (0,10-a), (1,9-a), (2,8-a), ... (10-a,0). As <em>a</em> runs from 0 to 10 we have total number of solutions (11-0)+(11-1)+...(11-1)=11+10+...+1=(1+11)*11/2=66.
Answer:
Don't subtract exactly or it will be incorrect, you'll have to add the years, and differentiate the leap years
Step-by-step explanation:
30 yrs old
sorry I dont have a shorter method
Answer:
Step-by-step explanation:
I will give each that is a statistical question
Subject the students in my class like.
Number of students in my class (as you could compare to another class)
height of each student
serving of fruits eaten in that month
Perhaps height (As you could compare it to the average height)
Highest temp. of each month this year.
How many students love football.
